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makkiz [27]
3 years ago
6

I'LL GIVE BRAINLIEST:

Mathematics
2 answers:
ioda3 years ago
8 0

Answer:

A

Step-by-step explanation:

VashaNatasha [74]3 years ago
4 0
B THE ANSWER because I just know that
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A compact disc has an approximate Radius of 2 3/8 inches, what is the approximate area of a CD
professor190 [17]

Answer:

A≈12.57      

r Radius 2

Step-by-step explanation:

6 0
3 years ago
Plz help for this answer
aleksandr82 [10.1K]

Answer:

wth is up with your workbook answer is 4 i think

Step-by-step explanation:

6 0
3 years ago
Find ML, JK=3x+11, ML=10x-12, NP=45
tigry1 [53]

Answer:

ML = 58

Step-by-step explanation:

Given

JK=3x+11, ML=10x-12, NP=45

See attachment

Required

Length ML

First, calculate x using the following equivalent ratios

JK : NP = NP : ML

Express as fraction

\frac{JK }{ NP} = \frac{NP }{ ML}

Cross Multiply

JK * ML = NP * NP

Substitute values:

(3x +11) * (10x - 12) = 45 * 45

Expand

30x^2 - 36x + 110x - 132 = 2025

30x^2 +74x - 132 = 2025

Collect like terms

30x^2 +74x - 132 - 2025=0

30x^2 +74x -2157=0

Using a calculator:

x \approx -10 and x \approx 7

Given that:

ML=10x-12

Substitute values for x

ML=10*-10-12 = -100 - 12 = -112

ML=10*7-12 = 70 - 12 = 58

ML cannot be negative; So:

ML = 58

5 0
3 years ago
What is the solution to the inequality? m/-2 <10
Anna11 [10]

Answer:

m>-20

Step-by-step explanation:

to leave m alone you need to multiply -2 to the other side but when you do that the sign changes because its by a negative.

7 0
3 years ago
he American Heart Association is about to conduct an anti-smoking campaign and wants to know the fraction of Americans over 45 w
Sonja [21]

Answer:

The 85% confidence interval is (0.2187, 0.2613).

Step-by-step explanation:

We have a large sample of size n = 830 Americans over 45. We have observed that 631 people don't smoke. Let p be the population proportion of Americans over 45 who smoke. An point estimate of p is \hat{p} = 199/830 = 0.24 and an estimate of the standard deviation of \hat{p} is \sqrt{\hat{p}(1-\hat{p})/n} = \sqrt{(0.24)(0.76)/830} = 0.0148. Therefore, because we have a large sample, the 85% confidence interval for the population proportion is given by \hat{p}\pm z_{\alpha/2}\sqrt{\hat{p}(1-\hat{p})/n} = 0.24\pm z_{0.15/2}0.0148 = 0.24\pm z_{0.075}0.0148 where z_{0.075} is the 7.5th quantile of the standard normal distribution, i.e., -1.4395. Therefore the 85% confidence interval is 0.24\pm (1.4395)(0.0148) or equivalently (0.2187, 0.2613).

7 0
3 years ago
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