Answer:
B. 785 M
Step-by-step explanation:
Circumference = 2*pi*r
C = 2 * pi * 125
C = 250pi This is the exact answer
Now approximating with pi as 3.14
C = 250 (3.14)
C = 785
The perimeter for the rectangle is 64.5m.
The answer is: z² .
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Given: <span>(x÷(y÷z))÷((x÷y)÷z) ; without any specified values for the variables;
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we shall simplify.
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We have:
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</span>(x÷(y÷z)) / ((x÷y)÷z) .
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Start with the first term; or, "numerator": (x÷(y÷z)) ;
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x ÷ (y / z) = (x / 1) * (z / y) = (x * z) / (1 *y) = [(xz) / y ]
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Then, take the second term; or "denominator":
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((x ÷ y) ÷z ) = (x / y) / z = (x / y) * (1 / z) = (x *1) / (y *z) = [x / (zy)]
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So (x÷(y÷z)) / ((x÷y)÷z) = (x÷(y÷z)) ÷ ((x÷y)÷z) =
[(xz) / y ] ÷ [x / (zy)] = [(xz) / y ] / [x / (zy)] =
[(xz) / y ] * [(zy) / x] ;
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The 2 (two) z's "cancel out" to "1" ; and
The 2 (two) y's = "cancel out" to "1" ;
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And we are left with: z * z = z² . The answer is: z² .
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Answer:
Step-by-step explanation:
7a-10c-2a-0.5c+5
5a-10.5c+5
it is your first choice
Answer:
Step-by-step explanation:
Given that X, the hip width of men is N(14.2, 0.9)
i.e. we have 
is N(0,1)
Seat width an airline uses = 16.7 inches.
a) the probability that if an individual man is randomly selected, his hip breadth will be greater than 16.7 in
b) Here sample size = 126
Each person is independent of the other
the probability that these men have a mean hip breadth greater than 16.7
=
<0.00001
c) part a is important since even a single person not fitting will cause embarassment and leads to customer dissatisfaction.
