Answer:
static electricity is a flowing charges
Answer: "For a projectile with no air resistance, at the peak of its path, it's velocity is equal to zero"
Explanation:
Suppose that you throw an object up. The initial vertical velocity will be positive, and the acceleration (the gravitational acceleration) will point downwards, meaning that it opposes to the initial direction of the velocity, and that decreases the velocity as the time goes by.
There will be a point where the velocity ( that was positive until now, so until now the height of the object was increasing), is equal to zero, this means that at this moment the object stops moving, and after, because we still have negative acceleration, the velocity will start become negative, and the object will fall down.
Then that point where the velocity was zero is the peak of its path, then we can conclude that:
"For a projectile with no air resistance, at the peak of its path, it's velocity is equal to zero"
Answer:
5m/s
Explanation:
equation for momentum is mass times velocity
25 x 5 = 125
Answer:
Explanation:
distance covered by ice cube = 0.5 m
force acting downwards = mgsin49
force of friction acting along surface upwards
= mgcos49 x .16 ( reaction force of inclined surface R = mgcos49.)
net force acting downwards
mgsin49 - mgcos49 x .16
mg (sin49 - cos49 x .16 )
net acceleration downwards
g (sin49 - cos49 x .16 )
= (.7547 - .105 ) x 9.8
= 6.367 m / s²
s = ut + 1/2 at²
0.5 = 0 + 1/2 x 6.367 x t²
t² = .1570
t = .4 s
b )
Let required inclination be θ
in the second case net acceleration
a = g ( sin θ - .385 cosθ )
s = ut + 1/2 at²
0.5 = 0 + 1/2 x g ( sin θ - .385 cosθ ) x .4 x .4
( sin θ - .385 cosθ ) = .6377
sin θ = .385 cosθ + .6377
θ = 58 degree.
kinematics allows to find the kinetic variables and the relationships between position, speed and acceleration, for launching projectiles we can find:
a) The horizontal velocity vₓ = 2.1 m/s
b) The height of the table y₀= 0.60 m
given parameters
- Time to reach the floor t = 0.35 s
- Horizontal distance x = 0.75 m
to find
a. Horizontal speed
b. table height
Let's use the kinematics relations, let's start by defining a reference frame with the x-axis along the motion of the ball and the vertical y-axis with the positive direction up.
We look for the initial velocity in the x axis, there is no acceleration we can use the uniform kinematic relations
vₓ = x / t
Where vx is the horizontal velocity, g the acceleration of gravity (g=9.8 m/s²) and t the time
vₓ = 0.75 / 0.35
vₓ = 2.14 m / s
We look for the height of the table that corresponds to the initial height (y₀) of the ball, when reaching the floor the height is zero, on the vertical axis the initial velocity is zero (v_{oy} = 0)
y = y₀ + v_{oy} t - ½ g t²
0 = y₀ + 0 - ½ g t²
y₀ = ½ g t²
y₀ = ½ 9.8 0.35²
y₀i = 0.60 m
- In conclusion with the kinematic relations for the launch of projectiles we can find the horizontal velocity vₓ = 2.1 m / s and the height of the table i = 0.60 m
learn more about projectile launch here:
brainly.com/question/12792922
