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3 years ago

6

. A car with a mass of 700-kg changes its speed from 10.0 m/s to 30.0 m/s in a displacement of 50.0 meters. Calculate the net fo

rce acting on the car during this time.

1 answer:

Nezavi [6.7K]3 years ago

6 0

Answer:

5600N

Explanation:

Given parameters:

Mass of car = 700kg

Initial velocity = 10m/s

Final velocity = 30m/s

Displacement = 50m

Unknown:

Net force acting on the car = ?

Solution:

To find the force acting on a body, it is pertinent we know the mass and acceleration.

Force = mass x acceleration

Now;

Let us find the acceleration from the kinematics equations:

v² = u² + 2aS

v is the final velocity

u is the initial velocity

a is the acceleration

S is the distance

30² = 10² + (2 x a x 50)

900 = 100 + 100a

100a = 800

a = 8m/s²

Therefore;

Force = 700 x 8 = 5600N

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During a plane showcase, a pilot makes circular "looping" with a speed equal to the sound speed (340 m/s). However, the pilot ca

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Answer:

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Explanation:

Data provided:

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here,

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Now,

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Two coconuts fall freely from rest at the same time, one from a tree twice as high as the other. If the coconut from the shorter

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Wee can use here kinematics

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An object is launched with an initial velocity of 50.0 m/s at a launch angle of 36.9∘ above the horizontal. part a determine x-v

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Given:
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θ = 36.9°, the launch angle above the horizontal

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The horizontal velocity is
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The horizontal distance traveled at time t is given in the table below.

Answer:

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A circular loop in the plane of a paper lies in a 0.45 T magnetic field pointing into the paper. The loop's diameter changes fro

Amanda [17]

Answer:

(A). The direction of the induced current will be clockwise.

(B). The magnitude of the average induced emf 16.87 mV.

(C). The induced current is 6.75 mA.

Explanation:

Given that,

Magnetic field = 0.45 T

The loop's diameter changes from 17.0 cm to 6.0 cm .

Time = 0.53 sec

(A). We need to find the direction of the induced current.

Using Lenz law

If the direction of magnetic field shows into the paper then the direction of the induced current will be clockwise.

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Using formula of flux

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Put the value into the formula

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We need to calculate the magnetic flux

Using formula of flux

$\phi_{2}=BA\cos\theta$

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$\phi_{2}=0.45\times(\pi\times(3\times10^{-2})^2)\cos0$

$\phi_{2}=0.00127\ Wb$

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Using formula of emf

$\epsilon=-N(\dfrac{\Delta \phi}{\Delta t})$

Put the value into t5he formula

$\epsilon=-1\times(\dfrac{0.00127-0.01021}{0.53})$

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(C). If the coil resistance is 2.5 Ω.

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Using formula of current

$I=\dfrac{\epsilon}{R}$

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$I=6.75\ mA$

Hence, (A). The direction of the induced current will be clockwise.

(B). The magnitude of the average induced emf 16.87 mV.

(C). The induced current is 6.75 mA.

5 0

3 years ago