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masha68 [24]
3 years ago
12

The direction of centripetal force is away from the axis of rotation.

Physics
2 answers:
Arada [10]3 years ago
4 0
I’m pretty sure it’s true x
Tomtit [17]3 years ago
3 0

Answer:

true

Explanation:

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When did forensic science start to become influential in solving crimes?
Dafna11 [192]

1900s -- 1980s

Forensic science R&D in the 1980s

6 0
2 years ago
A 10248 kg car is pulled by a low tow truck that has an acceleration of 2.0m/s what is the net force on the car
Ksenya-84 [330]

Answer: 20496N

Explanation:

The formula to calculate the net force will be given as:

Net force = Acceleration × Mass

Since 10248 kg car is pulled by a low tow truck that has an acceleration of 2.0m/s, the net force would be:

= 10248 × 2

= 20496N

8 0
3 years ago
You have a resistor of resistance 200 ? and a 6.00-?F capacitor. Suppose you take the resistor and capacitor and make a series c
Ne4ueva [31]

Answer:

eazy

Explanation:

hi bro it is very hard so I can't help and I don't the answer

4 0
4 years ago
I need to know the correct answer please ?
mrs_skeptik [129]

Answer:

675 Pa.

Explanation:

F = 5+2cos(15t) kN

Area (a) = 8*10-3 m2

Now at t =4 sec

            F= 5+2cos(60)

             = 5+2*0.5

              = 6  kN

Now ,force efficiency is 90%.

Hence,the effectively transmitted force,

            Fe = 0.90*6

                = 5.4 kN

Hence,pressure is given as,

            P = Fe/a

                = 5.4*10^3/(8 *10^-3))

              P = 675 Pa....answer

6 0
4 years ago
A ball is dropped from the top of a tower 40 m high. What is its velocity when it has covered 20 m? What would be its velocity w
stellarik [79]

Given :

Height from which ball is dropped , h = 40 m .

Acceleration due to gravity , g= 10 m/s² .

Initial velocity , u = 0 m/s .

To Find :

Velocity when ball covered 20 m and velocity when it hit the ground .

Solution :

Now , height when ball covered 20 m distance is , 40 - 20 = 20 m .

By equation of motion :

v^2=u^2+2gh\\\\v=\sqrt{2\times 10\times 20}\ m/s\\\\v=20\ m/s

Now , distance covered when body reaches ground is , 40 m .

Putting value h = 40 m in above equation , we get :

v=\sqrt{2\times 10\times 40}\ m/s\\\\v=20\sqrt{2}\ m/s

Hence , this is the required solution .

7 0
3 years ago
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