Answer:
Acceleration of the car is
.
Explanation:
It is given that,
Initial speed of the car, u = 29 m/s
Finally it reaches a speed of, v = 34 m/s
Distance, d = 110 m
We need to find the acceleration of the car as it speed up. It can be calculated using third law of motion as :




So, the acceleration of the car as it speeds up is
. Hence, this is the required solution.
Answer: 56.44°
Explanation:
<u>Given:</u>
- Let u represent the current speed of the plane, <u>1.2 Mach</u>
<em>Converting to SI Units (m/s):</em>
= (1.2 mach)(340 ms^-1 / 1 Mach)
u = 408 m/s
- Speed of sound in air, v = 340 m/s
<u>Find:</u>
- Angle the wave front of the shock wave relative to the plane's direction of motion, θ
We have, sinθ = speed of sound / speed of object
sinθ = v / u
θ = sin^-1 (v / u)
= sin^-1 (340 / 408)
θ = 56.44°
Answer:
https://www.slader.com/discussion/question/an-electron-is-accelerated-through-240-times-103-v-from-rest-and-then-enters-a-uniform-170-t-magnetic-field-what-are-a-the-maximum-and-b-the-9e425fbd/
( Here is solution)
Answer: Potassium(K)
Explanation:
its an alkali metal placed under sodium and its over rubidium, its also the first element of period 4
<span>The shortening velocity refers to the speed of the contraction from the muscle shortening while lifting a load. Maximal shortening velocity is only attained with a minimal load. With a light load, the shortening velocity is at its Maximal shortening velocity. When the weight is heavy, the speed in which the muscle lifts the weight decreases in speed at a slower velocity.</span>