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masha68 [24]
3 years ago
12

The direction of centripetal force is away from the axis of rotation.

Physics
2 answers:
Arada [10]3 years ago
4 0
I’m pretty sure it’s true x
Tomtit [17]3 years ago
3 0

Answer:

true

Explanation:

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A boxer punches a sheet of paper in midair and brings it from rest up to a speed of 30 m/s in 0.060 s .
zimovet [89]

Answer:

Force exerted, F = 1.5 N

Explanation:

It is given that, a boxer punches a sheet of paper in midair and brings it from rest up to a speed of 30 m/s in 0.060 s.

i.e. u = 0

v = 30 m/s

Time taken, t = 0.06 s

Mass of the paper, m = 0.003 kg

We need to find the force the boxer exert on it. The force can be calculated using second law of motion as :

F=m\times a

F=m\times (\dfrac{v-u}{t})

F=0.003\times (\dfrac{30}{0.06})

F = 1.5 N

So, the force the boxer exert on the paper is 1.5 N. Hence, this is the required solution.

6 0
3 years ago
How fast would you be going (in kmh) if you had a ship that accelerated at a constant 1g for 24 hours?
Nady [450]

Answer:

Explanation:

1 g is 9.8 m/s^2 the problem wants the results in km/h so we'll fix that really quick.

9.8 m/s^2 (1 km/1000m)(60 sec/1 min)^2(60 min/1 hour)^2 = 127008 km/hour^2

Now, I'm assuming the ship is starting from rest, and hopefully you know your physics equations.  We are going to use vf = vi + at.  Everything is just given, or we can assume, so I'll just solve.

vf = vi + at

vf = 0 + 127008 km/hour^2 * 24 hours

vf = 3,048,192 km/hour

If there's anything that doesn't make sense let me know.  

5 0
3 years ago
Initilal velocity of projectile at an angle of 22.5° is 10m/s. Then what is the magnitude of range of projectile?
crimeas [40]

Answer:

0.707m

Explanation:

from formula of range i.e R=Usin2Q/g

3 0
3 years ago
She left the cubes in the water for three hours which of the following describes a heat flow that took place during those three
quester [9]

Answer:

veffvevfevve

Explanation:

3 0
3 years ago
Read 2 more answers
If Scoobie could drive a Jetson's flying car at a constant speed of 450.0 km/hr across oceans and space, approximately how long
vladimir2022 [97]

Answer:

The value is t = 3.6 \  days

Explanation:

From the question we are told that

The speed is v  =  450.0 km/h

The radius of the earth is R =  6200 \  km

Generally the circumfernce of the earth is mathematically evaluated as

C =  2\pi  R

=> C =   2 * 3.142 *   6200

=> C =  38960.8 \ km

Generally the time taken is mathematically represented as

t =  \frac{38960.8}{450.0}

         t = 86.6 \  hr

Converting to days

         t = \frac{86.6}{24}

=>       t = 3.6 \  days

7 0
3 years ago
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