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Lerok [7]
3 years ago
8

A small 12.00 g plastic ball is suspended by a string in a uniform, horizontal electric field. If the ball is in equilibrium whe

n the string makes a 30 degrees angle with the vertical, what is the net charge on the ball?
Q = _______ C
Physics
1 answer:
notsponge [240]3 years ago
5 0

Answer:

Q = \frac{0.068}{E}

where E = electric field intensity

Explanation:

As we know that plastic ball is suspended by a string which makes 30 degree angle with the vertical

So here force due to electrostatic force on the charged ball is in horizontal direction along the direction of electric field

while weight of the ball is vertically downwards

so here we have

QE = F_x

mg = F_y

since string makes 30 degree angle with the vertical so we will have

tan\theta = \frac{F_x}{F_y}

tan30 = \frac{QE}{mg}

Q = \frac{mg}{E}tan30

Q = \frac{0.012\times 9.81}{E} tan30

Q = \frac{0.068}{E}

where E = electric field intensity

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Say a 14 year old girl was at a construction site and she was asked to move something like a 10,000 pound brick( one brick). She would be acting on it as the unbalanced force but they would still not change their position.

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Explanation:

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2 years ago
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Answer:

Distance = 3.69 × 10^9 m

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Explanation:

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Since a radio signal uses an electromagnetic wave to transfer signal, it has the same speed as the speed of light.

Speed of radio signal = speed of light = 3.0 × 10^8 m/s

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Substituting the values of speed and time into equation 1;

Distance = 3.0 × 10^8 m/s × 12.3 s

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Answer:

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3 years ago
Magnesium Oxide Reaction
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2 years ago
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