Answer:
The answer to your question is when time = 50 s, work = 5000 J
when time = 90 s, work = 9000 J
Explanation:
Data
time = 50 s or 90 s
Power = 100 watts
Power is defined as the rate of work done per unit of time.
Power = Work / time
-Solve for Work
Work = Power x time
-Substitution
Work = 100 x 50
-Result
Work = 5000
2.-When time = 90 s
Work = 100 x 90
-Result
Work = 9000 watts
A perfectly elastic<span> collision is defined as one in which there is no loss of </span>kinetic energy<span> in the collision. Therefore, we just add the kinetic energies of each system. We calculate as follows:
KE = 0.5(</span>1.0 × 10^3)(12.5 )^2 + 0.5(1.0 × 10^3)(12.5 )^2
KE = 156250 J = 1.6 x 10^5 J -------> OPTION A
Answer:
The magnetic force on the section of wire is 
.
Explanation:
Given that,
Current 
Length = 0.750 m
Magnetic field 
We need to calculate the magnetic force on the section of wire
Using formula of magnetic force
Since, 
Hence, The magnetic force on the section of wire is .
What r the answer choices? I'm
