Assuming you want to choose 4 people from the class of 20;
Begin by using the combinations formula;
20C4=4845 possibilities
Hope I helped :)
Answer:
x and y can have many values
Step-by-step explanation:
-24x - 12y = -16
Then: 24x + 12y = 16
We know: 6x + 3y = 4
X and Y can have a lot of valoues.
6x + 3y = 4
3 ( 2x + y) = 4
2x + y= 4/3
2x+y= 1.333...
These cannot be solved.- 3 unknowns require 3 equations
Make an equation.
80% = 0.8
'of' is multiplication
'what number' is 'x'
'is' is an equal sign
0.8 * x = 64
0.8x = 64
Divide 0.8 to both sides:
x = 80
