Answer: This problem statement does not provide a useful issue statement.
There are two ways to convert from hexadecimal to denary gcse method. They are:
- Conversion from hex to denary via binary.
- The use of base 16 place-value columns.
<h3>How is the conversion done?</h3>
In Conversion from hex to denary via binary:
One has to Separate the hex digits to be able to know or find its equivalent in binary, and then the person will then put them back together.
Example - Find out the denary value of hex value 2D.
It will be:
2 = 0010
D = 1101
Put them them together and then you will have:
00101101
Which is known to be:
0 *128 + 0 * 64 + 1 *32 + 0 * 16 + 1 *8 + 1 *4 + 0 *2 + 1 *1
= 45 in denary form.
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Answer:
2^32 times as many values can be represented
Explanation:
32-bit. This means that the number is represented by 32 separate one’s and zero’s. 32 bits of 2 possible states = 2^32=4,294,967,296 possible values.
Integer meaning that only whole multiples of one are accepted.
Signed meaning that negative values are accepted. This halves the number of possible positive values (roughly), so the largest number you can represent is 2^31–1=2,147,483,647, but instead of 0, the smallest number you can represent is -2,147,483,648. An unsigned 32-bit integer, by contrast, can represent anything from 0 to 4,294,967,295.
Answer:
I can :) just comment lol
