Answer:
The answer is "True".
Explanation:
The web beacons are one of the different techniques, that are used on web pages and emails, to check whether a user has access to some unobtrusively. It is a line, that is often invisible, and typically does not exceed 1 pixel.
- It is usually used with cookies.
- It is also known as a small graph, which generates a request to the server for tracking service.
Answer: Fixed layout
Explanation:
Fixed layout is the arrangement of any website page or webpage that is featured with fixed size on any screen resolution .Fixed layout displays all the components and tools of the page with a fixed percentage.
- The width or percentage cannot be changed or altered as it is fixed.The user experiences same width of the page and elements in any computing resolution.
Answer:
The hippocampus, a subcortical brain structure crucially involved in storing new information in memory, is smaller in people with schizophrenia and their first-degree relatives (parents and siblings) than in control participants.
StrawberryTeaa (could be any fruit: blueberry, peach, etc)
potatoxchip
pastelsquid
SquishyPeach
GummiBear
ElegantFlaws (could add an e and remove the s: EleganteFlaw)
hunnie_b (or honee, honnie, hunni, etc)
agonyisheree
It's cool if you don't like these. I had trouble when I changed my user too. But you'll find your perfect username eventually. :)
Answer:
Sequence of popped values: h,s,f.
State of stack (from top to bottom): m, d
Explanation:
Assuming that stack is initially empty. Suppose that p contains the popped values. The state of the stack is where the top and bottom are pointing to in the stack. The top of the stack is that end of the stack where the new value is entered and existing values is removed. The sequence works as following:
push(d) -> enters d to the Stack
Stack:
d ->top
push(h) -> enters h to the Stack
Stack:
h ->top
d ->bottom
pop() -> removes h from the Stack:
Stack:
d ->top
p: Suppose p contains popped values so first popped value entered to p is h
p = h
push(f) -> enters f to the Stack
Stack:
f ->top
d ->bottom
push(s) -> enters s to the Stack
Stack:
s ->top
f
d ->bottom
pop() -> removes s from the Stack:
Stack:
f ->top
d -> bottom
p = h, s
pop() -> removes f from the Stack:
Stack:
d ->top
p = h, s, f
push(m) -> enters m to the Stack:
Stack:
m ->top
d ->bottom
So looking at p the sequence of popped values is:
h, s, f
the final state of the stack:
m, d
end that is the top of the stack:
m
