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Doss [256]
3 years ago
10

Find the area of the largest square contained by a circle of radius r = 1cm. Explain your answer and justify that it is correct.

Hint: Use the pythagorean theorem.
Mathematics
1 answer:
Elena-2011 [213]3 years ago
7 0

Answer:

2 square cm

Step-by-step explanation:

Given :

A square is inscribed in a circle whose radius is r = 1 cm

Therefore, the diameter of the circle is 2 r = 2 x 1

                                                                      = 2 cm.

So the diagonal of the square is 2r.

Using the Pythagoras theorem, we find each of the side of the triangle is $r \sqrt 2$.

Therefore, the area of the square is given by $\text{(side)}^2$

                                                                         = $(r\sqrt 2)^2$

                                                                         $= 2 r^2$

                                                                         $= 2 (1)^2$

                                                                         $=2 \ cm^2$

Hence the area of the largest square that is contained by a circle of radius 1 cm is 2 cm square.

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T B'(4, -8) was transformed using the translation (x - 2, y + 3). What were the coordinates of B?
skad [1K]

Answer:

(6, -11)

Step-by-step explanation:

The translation (x-2,y+3) means "subtract 2 from x coordinate" and "add 3 to the y coordinate".

After the transformation, we have the point B'(4,-8). Which point, let it be (x,y), after being transformed is B'(4,-8)??

According to the transformation rule, we have to "subtract 2 from x coordinate" and "add 3 to the y coordinate", thus

x-2=4

x=4+2

x=6

and

y+3=-8

y=-8-3

y=-11

THe coordinate of B are (6,-11)

7 0
3 years ago
PLEASE HELP!!! I'LL GIVE YOU BRAINLIEST!
Andru [333]
(x - a)^2 + (y - b)^2 = (y - d)^2 

<span>x^2 - 2ax + a^2 + y^2 - 2by + b^2 = y^2 - 2dy + d^2 </span>

<span>Subtract y^2 from both sides... </span>

<span>x^2 - 2ax + a^2 - 2by + b^2 = -2dy + d^2 </span>

<span>Now I would just substitute in the the values (a = -4, b = 17/8, d = 15/8)... </span>

<span>x^2 - 2(-4)x + (-4)^2 - 2(17/8)y + (17/8)^2 = -2(15/8)y + (15/8)^2 </span>

<span>Simplify... </span>

<span>x^2 + 8x + 16 - (17/4)y + 289/64 = -(15/4)y + 225/64 </span>

<span>Add (17/4)y to both sides... </span>

<span>x^2 + 8x + 16 + 289/64 = (2/4)y + 225/64 </span>

<span>x^2 + 8x + 16 + 289/64 = (1/2)y + 225/64 </span>

<span>Subtract 225/64 from both sides... </span>

<span>x^2 + 8x + 16 + 1 = (1/2)y </span>

<span>x^2 + 8x + 17 = (1/2)y </span>

<span>Multiply both sides by 2... </span>

<span>2x^2 + 16x + 34 = y </span>

<span>...which is equal to equation D.</span>
8 0
3 years ago
Read 2 more answers
A bag of M&amp;M's contained 18 brown M&amp;M's out of 72 total in the bag. Predict how many brown M&amp;M's there would be in a
Anarel [89]

Think of it as a fraction >> 18/72

18/72 = .25 or 1/4 of the bag was with brown M&Ms

Now do 248 times .25 = 62 M&Ms

There you go. The answer is 62 Brown M&Ms

3 0
3 years ago
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19. A sample of 50 retirees is drawn at random from a normal population whose mean age and standard deviation are 75 and 6 years
Juliette [100K]

Answer:

a) Approximately normal.

b) The mean is 75 years and the standard deviation is 0.8485 years.

c) 0.9909 = 99.09% probability that the mean age exceeds 73 years

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

Sample of 50 retirees

This means that n = 50

Mean age and standard deviation are 75 and 6 years

This means that \mu = 75, \sigma = 6

a. Describe the shape of the sampling distribution of the sample mean in this case

By the Central Limit Theorem, approximately normal.

b. Find the mean and standard error of the sampling distribution of the sample mean.

By the Central Limit Theorem, the mean is 75 and the standard error is s = \frac{6}{\sqrt{50}} = 0.8485

c. What is the probability that the mean age exceeds 73 years?

This is 1 subtracted by the pvalue of Z when X = 73.

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{73 - 75}{0.8485}

Z = -2.36

Z = -2.36 has a pvalue of 0.0091

1 - 0.0091 = 0.9909

0.9909 = 99.09% probability that the mean age exceeds 73 years

5 0
2 years ago
115 = 20 + 2.5x<br> Answers <br> X= 38 <br> X= - 37/38
KIM [24]
The answer would be X=38
7 0
3 years ago
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