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Doss [256]
3 years ago
10

Find the area of the largest square contained by a circle of radius r = 1cm. Explain your answer and justify that it is correct.

Hint: Use the pythagorean theorem.
Mathematics
1 answer:
Elena-2011 [213]3 years ago
7 0

Answer:

2 square cm

Step-by-step explanation:

Given :

A square is inscribed in a circle whose radius is r = 1 cm

Therefore, the diameter of the circle is 2 r = 2 x 1

                                                                      = 2 cm.

So the diagonal of the square is 2r.

Using the Pythagoras theorem, we find each of the side of the triangle is $r \sqrt 2$.

Therefore, the area of the square is given by $\text{(side)}^2$

                                                                         = $(r\sqrt 2)^2$

                                                                         $= 2 r^2$

                                                                         $= 2 (1)^2$

                                                                         $=2 \ cm^2$

Hence the area of the largest square that is contained by a circle of radius 1 cm is 2 cm square.

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A number is 6 times another number and their difference is 30. What are the numbers? ​
Alenkasestr [34]

Answer:

x=36

y=6

Step-by-step explanation:

Let the numbers be x and y

Condition 1

x=6y ----------(1)

Condition 2

x-y=30 ------------(2)

Putting 1 in 2

6y-y=30

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Dividing both sides by 5

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Now

Putting y=6 in 1

We get

x=6(6)

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ehidna [41]

Answer:

\frac{1}{2} x⁸

Step-by-step explanation:

Given expression:

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