What is the value of the expression? (-2)3(-2)² 1 -64 -32 64
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Answer:
Acceleration of the particle =
Step-by-step explanation:
We are given the position vector of a particle moving in a circle of radius b units.
r(t) = b cos(ωt)i + b sin(ωt)j
Velocity , v = = -bω sin(ωt)i + bω cos(ωt)j
The magnitude of velocity, v =
Squaring both sides,
Since = 1
The acceleration towards the centre is called the centripetal acceleration and is given by
a =
a =
a =