Answer:
A Hercules Beetle is 6.97 inches larger than A ladybug
Step-by-step explanation:
A hercules beetle is 7 inches long while a ladybug is about 0.03 cm long when subtracting these two you will get a grand total of 6.97.
let's take admission fee= z
8z+11z=17.50+21.25
19z=38.75
z=38.25/19
z=2.4 (aprox)
Or In case of Kiara 17.50 amount paid in 8 rides
.so 1 ride=17.50/8
=2.1875
same In case of mia
so 1 ride=21.25/11
=1.9318.
but, they are not match so there is problem in your Questions.
So one trip = 4 km
two trips = 8
8 + 4 = 12
i believe your answer is 12
Thanks!
Answer: 2285.71
Step-by-step explanation:
Rearranging the simple interest formula, we have P = A / (1 + rt), where P is the Principal, r is the annaul rate and t is the time period.
r = R/100 = 5%/100 = 0.05 per year.
Solving the equation:
P = 3200 / ( 1 + (0.05 × 8)) = 2285.7142857143
Answer: 1.) x - 2y = 4 , add 2y to both sides. ---> answer is, X = 2y + 4
2.) 2x - 6y = 8, Add 6y to both sides, then divide both sides by 2. --> answer is, X = 3y + 4
