Hello
DEF and IKL , equilateral =>
DE = 5x-12 = 3x-4
5x-3x= -4+12
2x= 8
x=4
DE = 5x-12 = 20-12 = 8
KL = 3x+24 = 10x+3
24 -3 = 10x-3x
21 = 7x
x= 21/7 = 3
KJ = 10x+3 = 30+3 = 33
Looks like you have most of the details already, but you're missing one crucial piece.
is parameterized by
for 
and 
, and a normal vector to this surface is
with norm
So the integral of 
is
Answer:
82
Step-by-step explanation:
Let's first figure out what the first number is and use that to solve for the next. The problem states that the numbers are consecutive. So the 2nd number word be 1 plus the first.
The sum of 4 consecutive numbers:
1st = x
2nd = x + 1
3rd = x + 2
4th = x + 3
The sum of 4 consecutive number is 326.
1st + 2nd + 3rd + 4th = 326
x + (x + 1) + (x + 2) + (x + 3) = 326
Combine like terms:
4x + 6 = 326
Then we subtract 6 from both sides to isolate 4x:
4x + 6 - 6 = 326 - 6
4x = 320
Then we divide both sides by 4 to isolate x:
4x/4 = 320/4
x = 80
So the first number is 79
Now to get the second, let's just add 1.
80 + 1 = 81
Let's check if our answer would be correct:
80 + 81 + 82 + 83
= 326
First, X^2 while x is 4 =4^2, which is 4x4, which is 16
3X while x is 4 is 12. 16-12=4. So the answer is 4
