2 ^ 10 = 2¹⁰ = 1,024 .
2 ^ 10 este (2 x 2 x 2 x 2 x 2 x 2 x 2 x 2 x 2 x 2 ) (10 veces) tambien.
20x-28+12=16x+24 (i distributed the 4 to get this)
20x-16=16x+24 (added -28 & 12)
4x=40 (Subtracted 16x from both sides and added 16 to both sides)
(divide by 4 on both sides)
x=10
Answer: The smallest valuest value for<em> k </em>is 10, such that LCM o<em>f k</em> and 6 is 60.
Step-by-step explanation:
We know that, LCM = Least common multiple.
For example : LACM of 12 and 60 is 60.
If LCM of k and 6 is 60.
i.e. the least common multiple of k and 6 is 60.
Since, 10 x 6 = 60.
The smallest valuest value for<em> k </em>should be 10, such that LCM o<em>f k</em> and 6 is 60.
Hence, the smallest value of k is 10.
D, 495.
9 x 55 = 495, so nine containers can hold 495 balls.
