All categories

3 years ago

3-6i hi can you guys help me solve this, i’m not understanding it. construct a polynomial?

Mathematics

1 answer:

Lemur [1.5K]3 years ago

5 0

Answer:

Step-by-step explanation:

You subtract it and add the I

You might be interested in

Simplify fully: √18 / √8

sukhopar [10]

Sqrt18 = 3 sqrt2
sqrt 8 = 2 sqrt2

sqrt18 / sqrt 8 = 3 sqrt2 / 2 sqrt2 = 3/2 answer

4 0

3 years ago

Read 2 more answers

Please help! I’ll give brainliest

Vilka [71]

Answer:

Step 1: Simplify both sides of the equation.

−7f=12

Step 2: Divide both sides by -7.

−7f

−7

−12

Step-by-step explanation

sorry for the answer like this i couldnt find the fractions but the answer is f=-12/7 sorry :(

6 0

2 years ago

The length of a rectangle is 6 feet more than three times the width of the

Nesterboy [21]

Answer:

<h2>width = 6 feet</h2>

Step-by-step explanation:

let l be the length of the rectangle

let w be the width of the rectangle

The statement

The length of a rectangle is 6 feet more than three times the width of the

rectangle is written as

l = 6 + 3w

From the question

l = 24 feet

Substitute the value into the above formula and solve for the width

That's

24 = 6 + 3w

3w = 24 - 6

3w = 18

Divide both sides by 3

w = 6

Therefore

<h3>width = 6 feet</h3>

Hope this helps you

3 0

3 years ago

last night, julie's pet hamster zoe kept julie awake for at least an hour running on her exercise wheel and scratching at the co

borishaifa [10]

Answer: $x+y\geq 1$ , $x>\frac{1}{4}$ , $x\geq 2y$ and $y\geq 0$

Step-by-step explanation:

Here, x represents the number of hours Zoe spent running on her wheel and y represents the number of hours spent scratching her cage.

Julie was awoke for at least an hour running on her exercise wheel and scratching the of her cage.

⇒ $x+y\geq 1$

She ran on her wheel at least twice as long as she scratched at the corners of her cage.

⇒ $x\geq 2y$

Also, She spent more than 1/4 hour running on her wheel.

⇒ $x>\frac{1}{4}$

And, we know that number of hours can not be negative.

⇒ $y\geq 0$

Therefore, the complete system of inequality which shows the given situation is,

$x+y\geq 1$ , $x>\frac{1}{4}$ and $x\geq 2y$ , $y\geq 0$

Note: the feasible region ( covered by the given system) is shown in the below graph.

6 0

3 years ago

The point (-6, 4) is reflected over the x-axis.<br> What is the new point?

defon

Answer:

p (6, -4)-------------->p'(6,4)

7 0

3 years ago