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3 years ago

Why has it been difficult to pass laws regarding transportation?

Mathematics

1 answer:

Rzqust [24]3 years ago

6 0

Answer:

a-it would cause too much of a tax increase

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Combine like radicals to get your answer. image attached

spin [16.1K]

Answer:

So the final answer is

$-8\sqrt{3}$

Step-by-step explanation:

Radicals:

In mathematics, a radical expression is defined as any expression containing a radical (√) symbol. Many people mistakenly call this a 'square root' symbol, and many times it is used to determine the square root of a number. However, it can also be used to describe a cube root, a fourth root, or higher.

The given expression is

$-5\sqrt{3} -3\sqrt{3}$

Now take common radical out so we will get

$\sqrt{3}(-5-3)$

Now add the Parenthesis part.

$\sqrt{3}(-8)$

So the final answer is

$-8\sqrt{3}$

5 0

4 years ago

Who ever answers this problem incorrect gets brainliest

Lelu [443]

Answer:

umm there is no problem

Step-by-step explanation:

the answer is 10

3 0

3 years ago

Read 2 more answers

Danielle needs to earn $250 to pay for her vacation. She has $28 saved and she earns $12 per hour after taxes as a lifeguard. Ho

Taya2010 [7]

Answer:

Step-by-step explanation:

3 0

4 years ago

Mr. Good Wrench advertises that a customer will have to wait no more than 30 minutes for an oil change. A sample of 26 oil chang

Andru [333]

Answer:

The 90% confidence interval for the population standard deviation waiting time for an oil change is (3.9, 6.3).

Step-by-step explanation:

The (1 - α)% confidence interval for the population standard deviation is:

$CI=\sqrt{\frac{(n-1)s^{2}}{\chi^{2}_{\alpha/2, (n-1)}}}\leq \sigma\leq \sqrt{\frac{(n-1)s^{2}}{\chi^{2}_{1-\alpha/2, (n-1)}}}$

The information provided is:

n = 26

s = 4.8 minutes

Confidence level = 90%

Compute the critical values of Chi-square as follows:

$\chi^{2}_{\alpha/2, (n-1)}=\chi^{2}_{0.10/2, (26-1)}=\chi^{2}_{0.05, 25}=37.652$

$\chi^{2}_{1-\alpha/2, (n-1)}=\chi^{2}_{1-0.10/2, (26-1)}=\chi^{2}_{0.95, 25}=14.611$

*Use a Chi-square table.

Compute the 90% confidence interval for the population standard deviation waiting time for an oil change as follows:

$CI=\sqrt{\frac{(n-1)s^{2}}{\chi^{2}_{\alpha/2, (n-1)}}}\leq \sigma\leq \sqrt{\frac{(n-1)s^{2}}{\chi^{2}_{1-\alpha/2, (n-1)}}}$

$=\sqrt{\frac{(26-1)\times 4.8^{2}}{37.652}}\leq \sigma\leq \sqrt{\frac{(26-1)\times 4.8^{2}}{14.611}}\\\\=3.9113\leq \sigma\leq 6.2787\\\\\approx 3.9 \leq \sigma\leq6.3$

Thus, the 90% confidence interval for the population standard deviation waiting time for an oil change is (3.9, 6.3).

3 0

3 years ago

Petersons bought 249,000 townhome. They made a down payment of $42000.00 and took mortgage for the rest. Over the course of 30 y

xenn [34]

Answer:

Answer in photo

6 0

3 years ago