The answer is 1 and 7/8, all you have to do is turn the 3/4 into eighths.
Answer:
The answer is undefined.
Step-by-step explanation:
Slope is found using this equation: y-y1/x-x1. Fill in the coordinates to this equation. It should now look like this. -7--3/-5--5. When subtracting from two negatives, it changes into a positive. For example, -7--3 becomes -7+3, which equals -4. The same thing applies for the second part. -5--5 becomes -5+5, which equals 0. So, your slope is -4/0. However, when a 0 is in the denominator, it becomes undefined. So, the answer is undefined.
Answer:
388.5yd²
Step-by-step explanation:
We have Triangle TUV
In the question, we are given already
Angle U = 32°
Angle T = 38°
Angle V = ???
Side t = 31yd
Side u = ?
Side v = ?
Area of the triangle= ?
Step 1
We find the third angle = Angle V
Sum of angles in a triangle = 180°
Third angle = Angle V = 180° - (32 + 38)°
= 180° - 70°
Angle V = 110°
Step 2
Find the sides u and v
We find these sides using the sine rule
Sine rule or Rule of Sines =
a/ sin A = b/ Sin B
Hence for triangle TUV
t/ sin T = u/ sin U = v/ sin V
We have the following values
Angle T = 38°
Angle U = 32°
Angle V = 110°
We are given side t = 31y
Finding side u
u/ sin U= t/ sin T
u/sin 32 = 31/sin 38
Cross Multiply
sin 32 × 31 = u × sin 38
u = sin 32 × 31/sin 38
u = 26.68268yd
u = 26.68yd
Finding side x
v / sin V= t/ sin T
v/ sin 110 = 31/sin 38
Cross Multiply
sin 110 × 31 = v × sin 38
v = sin 110 × 31/sin 38
v = 47.31573yd
v = 47.32yd
To find the area of triangle TUV
We use heron formula
= √s(s - t) (s - u) (s - v)
Where S = t + u + v/ 2
s = (31 + 26.68 + 47.32)/2
s = 52.5
Area of the triangle = √52.5× (52.5 - 31) × (52.5 - 26.68 ) × (52.5 - 47.32)
Area of the triangle = √150967.6032
Area of the triangle = 388.5454973359yd²
Approximately to the nearest tenth =388.5yd²
Answer:
x = 6
Step-by-step explanation:
Hope this helps!
=)
Answer:
∠ BAC = 80°
Step-by-step explanation:
The sum of the interior angles of quadrilateral ACDB = 360°
DB and DC are tangents to the circle, thus
∠ DBA = ∠ ACD = 90° ( angle between tangent/ circle at point of contact )
Thus
∠ BAC + 90° + 90° + 100° = 360°
∠ BAC + 280° = 360° ( subtract 280° from both sides )
∠ BAC = 80°
