Decimal number between 0.25 and 0.5

pshichka [43]

Answer:

19 units, left

Step-by-step explanation:

You can use a graphing tool or create a graph to show how these lines relate to one another. Then, count the units that have been translated and where the translation occurred.

4 0

3 years ago

Julia has 4 gallons 2 quarts of water.Ally needs the same amount of water but only has 12 quarts.How much more water does Ally n

denis-greek [22]

Well there are 4 quarts to a gallon and 4 / 12 = 3 so she has 3 gallons so she needs 1 gallon and 2 quarts
so the answer is 1Gallon and 2Quarts

7 0

4 years ago

3. State if each statement is correct. If it is not correct, then fix the mistake.

olya-2409 [2.1K]

Answer:

All are incorrect

Step-by-step explanation:

Required

Determine which is correct or not

$(a)\ 2x * 2x = 4x$

This is incorrect because:

$2x * 2x = 2 * 2 * x*x$

$2x * 2x = 4x^2$ ---- fixed

$(b)\ 3x^3 * 3x^3 = 9x^9$

This is incorrect because:

$3x^3 * 3x^3 = 3 * 3 * x^3 * x^3$

$3x^3 * 3x^3 = 9x^(3+3)$

$3x^3 * 3x^3 = 9x^6$ ---- fixed

$(c)\ 4x(4x + 5) =8x + 5$

This is incorrect because:

$4x(4x + 5) =4x * 4x + 4x * 5$

$4x(4x + 5) =16x^2 + 20x$ ---- fixed

4 0

3 years ago

. Lightning Strikes It has been said that the probability of being struck by lightning is about 1 in 750,000, but under what cir

mrs_skeptik [129]

Complete Question

The complete question is shown on the first uploaded image

Answer:

a

$P(U |D ) = 0.198$

b

$P(O\ n \ B) = 0.188$

c

$P(O | B) = 0.498$

Step-by-step explanation:

The total number of deaths is mathematically represented as

$T = 16 + 23 + \cdots + 16$

$T =623$

The total number of deaths in 1996 - 2000 is mathematically represented as

$T_a = 16 + 23+ \cdots + 30$

$T_a = 235$

The total number of deaths in 2001 - 2005 is mathematically represented as

$T_b = 17 + 16 + \cdots + 23$

$T_b = 206$

The total number of deaths in 2006 - 2010 is mathematically represented as

$T_c = 15 + 17 + \cdots + 16$

$T_d = 182$

Generally the the probability that it would occur under the tree given that the death was after 2000 is mathematically represented as

$P(U |D ) = \frac{P(A \ n\ U )}{P(A)}$

Here $P(A \ n\ U )$ represents the probability that it was after 2000 and it was under the tree and this is mathematically represented as

$P(A \ n\ U ) = \frac{Z}{ T}$

Here Z is the total number of death under the tree after 2000 and it is mathematically represented as

$Z = 35 + 42$

=> $Z = 77$

=> $P(A \ n\ U ) = \frac{77}{ 623}$

=>

Also

$P(A)$ is the probability of the death occurring after 2000 and this is mathematically represented as

$P(A) = \frac{T_b + T_c}{ T}$

=> $P(A) = \frac{ 206+ 182}{623}$

=>

So

$P(U |D ) = \frac{\frac{77}{ 623} }{ \frac{ 206+ 182}{623}}$

=> $P(U |D ) = 0.198$

Generally the probability that the death was from camping or being outside and was before 2001 is mathematically represented as

$P(O | B) = \frac{T_z}{ T}$

Here $T_z$ is the total number of death outside / camping before 2001 and the value is 117

So

$P(O \ n \ B) = \frac{117}{623}$

=> $P(O\ n \ B) = 0.188$

Generally the probability that the death was from camping or being outside given that it was before 2001 is mathematically represented as

$P(O | B) = \frac{ P( O \ n \ B)}{ P(B)}$

Here $P(B)$ is the probability that it was before 2001 , this is mathematically represented as

$P(B ) = \frac{T_a}{T}$

=> $P(B ) = \frac{235}{623}$

So

$P(O | B) = \frac{ \frac{117}{623}}{ \frac{235}{623}}$

=> $P(O | B) = 0.498$

5 0

3 years ago

Standard form..........

Aliun [14]

0.008
Hope this helps!

6 0

4 years ago

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