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sashaice [31]
3 years ago
9

Compare and Contrast Graph y = 2x + 5 and y=-13x+5. Describe how these lines are alike and how they are different. *​

Mathematics
1 answer:
krek1111 [17]3 years ago
4 0

Here are a couple I found:

<u>Similarities</u>:

  • They have the same y-intercept of (0,5).
  • They are both in slope-intercept form.

<u>Differences</u>:

  • The line of y = -13x + 5 "falls" from left to right. The line of y = 2x + 5 "rises" from left to right.
  • They have different x-intercepts. (y = 2x + 5 intersects (-\frac{5}{2}, 0) while y = -13x + 5 intersects at (\frac{5}{13}, 0)

<u></u>

<u>Explanation</u>:

Slope-intercept form is y = mx + b, and by looking at the equations, they both already fit that format, with m as their slope and b as their y-intercept. Also, since they both have a 5 as that "b," their y-intercepts are the same: (0,5).

As for differences, we can see that the coefficient in place of that "m" is positive in y = <u>2x</u> + 5 and negative in y = <u>-13x</u> + 5. Therefore, one line would rise due to their slope being positive and one would fall due to their slope being negative. They also have two different x-intercepts, which we can calculate by substituting 0 in place of the y, then isolating x.

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RR = [[ ( 2/5 * 1/3 ) + ( 2/3 * 2/3 ) ] * [( 1/2 * 1/3 ) + ( 4/5 * 2/3 ) ]] = 0.4

RB = [[ (2/5 * 1/3 ) + ( 2/3 * 2/3 ) ] * [ ( 3/4 *1/3 ) + ( 2/5 * 2/3 ) ]] ≈ 0.3

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BR = [[ ( 3/5 * 1/3 ) + ( 1/3 * 2/3 ) ] * [ ( 1/2 * 1/3 ) + ( 4/5 * 2/3 ) ]] ≈ 0.30

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