Compare and Contrast Graph y = 2x + 5 and y=-13x+5. Describe how these lines are alike and how they are different. *

Mathematics

1 answer:

krek1111 [17]2 years ago

4 0

Here are a couple I found:

Similarities:

They have the same y-intercept of (0,5).
They are both in slope-intercept form.

Differences:

The line of y = -13x + 5 "falls" from left to right. The line of y = 2x + 5 "rises" from left to right.
They have different x-intercepts. (y = 2x + 5 intersects (- $\frac{5}{2}$ , 0) while y = -13x + 5 intersects at ( $\frac{5}{13}$ , 0)

Explanation:

Slope-intercept form is y = mx + b, and by looking at the equations, they both already fit that format, with m as their slope and b as their y-intercept. Also, since they both have a 5 as that "b," their y-intercepts are the same: (0,5).

As for differences, we can see that the coefficient in place of that "m" is positive in y = 2x + 5 and negative in y = -13x + 5. Therefore, one line would rise due to their slope being positive and one would fall due to their slope being negative. They also have two different x-intercepts, which we can calculate by substituting 0 in place of the y, then isolating x.

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3 years ago

Consider the polynomial f(x) = 5x4+ 3x2+ x + 19. How many complex solutions does the polynomial have?

antiseptic1488 [7]

Answer:

there are 4 complex solutions
3 real zeros and 2 complex zeros

Step-by-step explanation:

1. Descarte's rule of signs tells you there are 0 positive real roots and 0 or 2 negative real roots. (for positive x, signs are ++++ so have no changes; for negative x, signs are ++-+, so have 2 changes.) A graph shows no real roots.

2. There are 3 sign changes in the given polynomial, so 3 or 1 positive real roots. When the sign of x is changed, there are 2 sign changes, so 0 or 2 negative real roots. A graph shows 2 negative and one positive real root (for a total of 3), so the remaining 2 roots are complex.