Answer:
We can claim with 95% confidence that the proportion of executives that prefer trucks is between 19.2% and 32.8%.
Step-by-step explanation:
We have a sample of executives, of size n=160, and the proportion that prefer trucks is 26%.
We have to calculate a 95% confidence interval for the proportion.
The sample proportion is p=0.26.
The standard error of the proportion is:
The critical z-value for a 95% confidence interval is z=1.96.
The margin of error (MOE) can be calculated as:
Then, the lower and upper bounds of the confidence interval are:
The 95% confidence interval for the population proportion is (0.192, 0.328).
We can claim with 95% confidence that the proportion of executives that prefer trucks is between 19.2% and 32.8%.
I'm pretty sure it's 7 and 1/7
Answer:
0.6603 = 66.03% probability that it will be sent with the ABC Speedy Delivery Company and arrive on time.
Step-by-step explanation:
Conditional Probability
We use the conditional probability formula to solve this question. It is
In which
P(B|A) is the probability of event B happening, given that A happened.
is the probability of both A and B happening.
P(A) is the probability of A happening.
In this question:
Event A: Sent by ABC Speedy Delivery Service.
Event B: Arrived on time.
The probability that any given parcel will be sent by the ABC Speedy Delivery Service is 0.71.
This means that 
The probability that the parcel will arrive on time given the ABC Speedy Delivery Company was used is 0.93.
This means that 
Find the probability that it will be sent with the ABC Speedy Delivery Company and arrive on time.
This is . So
0.6603 = 66.03% probability that it will be sent with the ABC Speedy Delivery Company and arrive on time.
Answer:
V= 36 9/16 or (decimal form) 36.5625
Step-by-step explanation:
V=length x width x height
STAN TXT AND STREAM IF BORED
