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Sonbull [250]
4 years ago
13

Troy and Lisa were shopping for school supplies. Each purchased different quantities of the same notebook and thumb drive. Troy

bought 6 notebooks and 7thumb drives for 185$. Lisa bought 14 notebooks and 12 thumb drives for 332$. Find the cost of each notebook and thumb drive
Mathematics
1 answer:
kari74 [83]4 years ago
4 0

Answer:

Notebook is $4

Thumb drive is $23

Step-by-step explanation:

Let notebooks be x and thumb drives be y

6x+7y=$185

14x+12y=$332

These two are simultaneous equation. Multiplying the first equation by 7 and second by 3 we obtain

42x+49y=$1295

42x+36y=$996

Subtracting the third equation from the fourth

996-1295=-$299

(36-49)y=-23y

-23y=-$299

y=$299/13=$23

To get the value of x, we substitute the value of y into the first equation

6x+(7*23)=$185

6x=$185-$161

6x=$24

x=$4

Therefore, price of notebook is $4, price of thumb drive is $23

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iogann1982 [59]
<h2>Hello!</h2>

The answer is:

The maximum height before landing will be 69.7804 feet.

<h2>Why?</h2>

Since there is no information about the angle of the launch, we can safely assume that it's launched vertically.

So, we can calculate the maximum height of the pumpkin using the following formulas:

y=y_o+v_{o}*t-\frac{1}{2}gt^{2}

v=vo-gt

Where,

y, is the final height

y_o, is the initial height

g, is the acceleration of gravity , and it's equal to:

g=32.2\frac{ft}{s^{2} }

t, is the time.

Now, we are given the following information:

y_{o}=12ft\\\\v=61\frac{ft}{s}

Then, to calculate the maximum height, we must remember that at the maximum height, the speed tends to 0, so, calculating we have:

Time calculation,

We need to use the following equation,

v=vo-gt

So, substituting we have:

v=61\frac{ft}{s}-32.2\frac{ft}{s^{2}}*t\\\\-61\frac{ft}{s}=-32.2\frac{ft}{s^{2}}*t\\\\t=\frac{-61{ft}{s}}{-32.2\frac{ft}{s^{2}}}=1.8944s

We know that it will take 1.8944 seconds to the pumpkin to reach its maximum height.

Maximum height calculation,

Now, calculating the maximum height, we need to use the following equation:

y=y_o+v_{o}*t-\frac{1}{2}gt^{2}

Substituting and calculating, we have:

y=y_o+v_{o}*t-\frac{1}{2}gt^{2}

y=12ft+61\frac{ft}{s}*1.8944s-\frac{1}{2}32.2\frac{ft}{s^{2}}*(1.8944s)^{2}

y=12ft+61\frac{ft}{s}*1.8944s-\frac{1}{2}32.2\frac{ft}{s^{2}}*(1.8944s)^{2}\\\\y_{max}=12ft+115.5584ft-16.1\frac{ft}{s^{2}}*(3.5887s^{2})\\\\y_{max}=127.5584ft-57.7780ft=69.7804ft

Hence, we have that the maximum height before the landing will be 69.7804 feet.

Have a nice day!

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Answer:

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Step-by-step explanation:

This is an arithmetic sequence with n th term

a_{n} = a₁ + (n - 1)d

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here d = 2 - (- 1) = 5 - 2 = 8 - 5 = 3 and a₁ = - 1, so

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Answer:

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Since you know that r = 9 and t = 11, you can substitute the variables to numbers. Then you just multiply to get 198. Hope this helps :)

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