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Answer:
4(2e - 3)(3e + 1)
Step-by-step explanation:
Given
24e² - 28e - 12 ← factor out 4 from each term
= 4(6e² - 7e - 3) ← factor the quadratic
Consider the factors of the product of the e² term and the constant term which sum to give the coefficient of the e- term.
product = 6 × - 3 = - 18 and sum = - 7
The factors are - 9 and + 2
Use these factors to split the e- term
6e² - 9e + 2e - 3 ( factor the first/second and third/fourth terms )
= 3e(2e - 3) + 1 (2e - 3) ← factor out (2e - 3) from each term
= (2e - 3)(3e + 1)
Then
24e² - 28e - 12 = 4(2e - 3)(3e + 1) ← in factored form
Answer: I need points
Step-by-step explanation:
Yep. Dkjdjdndn dkjdjdndn
Answer: 40x+18
Step-by-step explanation:
Step-by-step explanation:
h(x) = 3. g(x) + 5
x= -1 h(x) = 3×8 + 5= 29
x= 0h(x) = 3×5 + 5= 20
x= 2 h(x) = 3×1 + 5= 8
x= 5 h(x) = 3×-5 + 5= -10
