Please solve this dont give stupid answer for credit.....

1 answer:

mart [117]3 years ago

6 0

(i)

∠BAD + ∠ABD + ∠ADB = 180 <em>the sum of the angles of a triangle equals 180°</em>

70 + 50 + ∠ADB = 180 <em>substituted given information</em>

∠ADB = 60 <em>subtraction property (subtracted 70 and 50)</em>

∠ABD + ∠BDC = ∠ADC <em>angle addition property</em>

60 + ∠BDC = 80 <em>substituted solved and given information</em>

∠BDC = 20 <em>subtraction property</em>

(ii) SORRY but I'm not sure how to find ∠BCD. If ∠ADC = ∠ABC, then ∠DBC = 30. We already calculated ∠BDC = 20, which means that ∠BCD = 130

(iii)

∠BCA = ∠ADB <em>given as a hint</em>

∠BCA = 60 <em>substituted ∠ADB that was solved in part (i)</em>

Answer: (i) = 20, (ii) = 130?, (iii) = 60

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Pachacha [2.7K]

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So 30 North american: 18 South american, and : 12 European. Hope it helps!

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4 years ago

tamaranim1 [39]

The above question is a mathematical proof of the relationship between Lines and angles related to a Rhombus. See the proof below.

<h3>What is a Rhombus?</h3>

A Rhombus is a parallelogram with four sides (that is a quadrilateral). It's sides however are all of equal length.

<h3>What is the above proof?</h3>

∠DEC ≅ ∠BFC Reason = All Right Angles with Equal dimensions are congruent.

∠C ≅ ∠C Reason = It is the same angle for the two Right angles above which are congruent, hence Reflexive Property.
Δ DEC ≅ Δ BFC Reason = Angle Angle Side. The triangles are said to be congruent when two angles and a non-included side of one triangle match the corresponding angles and sides of another triangle.
$\overline {DC}$ ≅ $\overline {BC}$ Reason = The corresponding parts of congruent triangles are congruent. Also, it is a parallelogram with all congruent sides.
ABCD is a Rhombus Reason = Its sides are all congruent.