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3 years ago

There are 15 students on a yearbook committee. 40% of the students are females. How many students on the committee are males?

Mathematics

2 answers:

Andrei [34K]3 years ago

8 0

Answer:

9 students on the committee are males

Step-by-step explanation:

As per the statement:

There are 15 students on a yearbook committee.

⇒Total students on a yearbook committee = 15

⇒ $\text{Male students} +\text{Female students} = 15$ ....[1]

It is given that:

40% of the students are females

⇒ $\text{Female students} = \frac{40}{100} \cdot 15 = 6$

Substitute in [1] we have;

$\text{Male students} + 6 = 15$

Subtract 6 from both sides we have;

$\text{Male students}= 9$

Therefore, 9 students on the committee are males

uranmaximum [27]3 years ago

3 0

Answer:

its 9

Step-by-step explanation:

100-40=60

60% of 15 is 9

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Mikhael wanted to rewrite the conversion factor "1 yard ≈ 0.914 meter" to create a conversion factor to convert meters to yards.

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Answer:

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Step-by-step explanation:

Given

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Required

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$\frac{1\ yard}{0.914} = \frac{0.914\ meter}{0.914}$

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2 years ago

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Answer:

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Step-by-step explanation:

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2 years ago

The school concert raised $1360 from the sale of 400 tickets. If adult tickets cost $5 and student tickets $3, how many student

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3 years ago

Maths functions question!!

Marina86 [1]

Answer:

5) DE = 7 units and DF = 4 units

6) ST = 8 units

$\textsf{7)} \quad \sf OM=\dfrac{3}{2}\:units$

8) x ≤ -3 and x ≥ 3

Step-by-step explanation:

<u>Information from Parts 1-4:</u>

brainly.com/question/28193969

$f(x)=-x+3$

$g(x)=x^2-9$

A = (3, 0) and C = (-3, 0)

Points A and D are the <u>points of intersection</u> of the two functions.

To find the x-values of the points of intersection, equate the two functions and solve for x:

$\implies g(x)=f(x)$

$\implies x^2-9=-x+3$

$\implies x^2+x-12=0$

$\implies x^2+4x-3x-12=0$

$\implies x(x+4)-3(x+4)=0$

$\implies (x-3)(x+4)=0$

Apply the zero-product property:

$\implies (x-3)= \implies x=3$

$\implies (x+4)=0 \implies x=-4$

From inspection of the graph, we can see that the x-value of point D is <u>negative</u>, therefore the x-value of point D is x = -4.

To find the y-value of point D, substitute the found value of x into one of the functions:

$\implies f(-4)=-(-4)=7$

Therefore, D = (-4, 7).

The length of DE is the difference between the y-value of D and the x-axis:

⇒ DE = 7 units

The length of DF is the difference between the x-value of D and the x-axis:

⇒ DF = 4 units

To find point S, substitute the x-value of point T into function g(x):

$\implies g(4)=(4)^2-9=7$

Therefore, S = (4, 7).

The length ST is the difference between the y-values of points S and T:

$\implies ST=y_S-y_T=7-(-1)=8$

Therefore, ST = 8 units.

The given length of QR (⁴⁵/₄) is the difference between the functions at the same value of x. To find the x-value of points Q and R (and therefore the x-value of point M), subtract g(x) from f(x) and equate to QR, then solve for x:

$\implies f(x)-g(x)=QR$