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lukranit [14]
4 years ago
6

Pencils are sold in packages of 5 explain why you need 6 packages in order to have enough for 27 students

Mathematics
1 answer:
Semmy [17]4 years ago
5 0
You need 6 packages because 5 packages wont be enough pencils for all of the students. You see, 5 times 5 is 25, and we have 27 students. So we buy 6 and have extra.
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Which of the following gives the correct intercept points and vertex point for the function ƒ(x) = x2 + 5x + 6?
Alex17521 [72]

Answer:

(-5/2,-1/4)

Step-by-step explanation:

7 0
3 years ago
Complete the steps to find the value of x
Anastasy [175]

Answer:

x=7

Step-by-step explanation:

(8x+6)=m∠4

m∠4 + 118 = 180

(8x + 6) +118 = 180

(8x + 6) + 118 - 118 = 180 - 118

8x + 6 = 62

8x = 56

x = 7

Hope this helps!!!

3 0
3 years ago
Someone plssss helppppp i need it finished in like 20 min plsss help
denis23 [38]

Answer:

number of guest tickets, g, is 100 tickets

number of student tickets, s, is 125 tickets

Step-by-step explanation:

Given;

total number of tickets sold, t = 225 tickets

cost of each guest ticket,  = $5.5

cost of each student ticket, = $3.5

total cost of the tickets, Tc = $987.5

number of guest tickets = g

number of student tickets, = s

g(5.5) + s(3.5) = 987.5 ------- (1)

g + s = 225 ----------- (2)

From equation (2); s = 225 - g

Substitute the value of g in equation (1)

5.5g + 3.5(225 - g) = 987.5

5.5g + 787.5 - 3.5g = 987.5

5.5g - 3.5g = 987.5 - 787.5

2g = 200

g = 200 / 2

g = 100 tickets

Then, s = 225 - g

s = 225 - 100

s = 125 tickets

3 0
3 years ago
One method of slowing the growth of an insect population without using pesticides is to introduce into the population a number o
Zielflug [23.3K]

To be clear, the given relation between time and female population is an integral:<span>
</span>t = \int { \frac{P+S}{P[(r - 1)P - S]} } \,&#10;dP<span>

</span>

<span>The problem says that r = 1.2 and S = 400, therefore substituting:<span>
</span>t = \int { \frac{P+400}{P[(1.2 - 1)P - 400]}&#10;} \, dP<span>

</span>= <span><span>&#10;\int { \frac{P+400}{P(0.2P - 400)} } \, dP

In order to evaluate this integral, we need to write this rational function in a simpler way:
</span>\frac{P+400}{P(0.2P - 400)} = \frac{A}{P} +&#10;\frac{B}{(0.2P - 400)}</span><span>

</span>where we need to evaluate A and B. In order to do so, let's calculate the LCD:<span>
</span>\frac{P+400}{P(0.2P - 400)} = \frac{A(0.2P -&#10;400)}{P(0.2P - 400)} + \frac{BP}{P(0.2P - 400)}<span>

</span>the denominators cancel out and we get:<span>
</span>P + 400 = 0.2AP - 400A + BP<span>
</span>             = P(0.2A + B) - 400A<span>

</span>The two sides must be equal to each other, bringing the system:<span>
</span>\left \{ {{0.2A + B = 1} \atop {-400A =&#10;400}} \right.<span>

</span>Which can be easily solved:<span>
</span>\left \{ {{B=1.2} \atop {A=-1}} \right.<span>

</span>Therefore, our integral can be written as:<span>
</span>t = \int { \frac{P+400}{P(0.2P - 400)} } \,&#10;dP = \int {( \frac{-1}{P} + \frac{1.2}{0.2P-400} )} \, dP<span>
</span>= - \int { \frac{1}{P} \, dP +&#10;1.2\int { \frac{1}{0.2P-400} } \, dP<span>
</span>= - \int { \frac{1}{P} \, dP +&#10;6\int { \frac{0.2}{0.2P-400} } \, dP<span>
</span>= - ln |P| + 6 ln |0.2P - 400| + C<span>

</span>Now, let’s evaluate C by considering that at t = 0 P = 10000:<span>
</span>0 = - ln |10000| + 6 ln |0.2(10000) - <span>400| + C
C = ln |10000</span>| - 6 ln |1600|<span>
</span>C = ln (10⁴) - 6 ln (2⁶·5²)<span>
</span>C = 4 ln (10) - 36 ln (2) - 12 ln (5) <span><span>
</span></span><span><span> </span>Therefore, the equation relating female population with time requested is:<span>
</span><span>t =  - ln |P| + 6 ln |0.2P - 400| + 4 ln (10) - 36 ln </span>(2) - 12 ln (5)</span></span>
8 0
3 years ago
Please help........................
Rama09 [41]

Answer:

x = 7

Step-by-step explanation:

Since BD is the angle bisector of ∠ABC, then

∠ABD = ∠CBD, that is

2x + y = 14 + y ( subtract y from both sides )

2x = 14 ( divide both sides by 2 )

x = 7

8 0
3 years ago
Read 2 more answers
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