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andreyandreev [35.5K]
3 years ago
6

The sum of two consecutive integers is 23. what are the integers?

Mathematics
1 answer:
Zepler [3.9K]3 years ago
3 0

Let the consecutive integers be x and x+1.

Then,

x + (x + 1) = 23

=> x + x + 1 = 23

=> 2x + 1 = 23

=> 2x = 23 - 1

=> 2x = 22

=> x = 22/2

=> x = 11

So, the integers are:

x = 11

and x + 1 = 11 + 1 = 12

So, the consecutive integers are 11 and 12.

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solniwko [45]

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a

Step-by-step explanation:

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alukav5142 [94]

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Step-by-step explanation:

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3 years ago
Rafael is ordering an ice cream dessert. He must order a size, a flavor of ice cream, and a topping. There are 3 sizes, 3 flavor
Pavlova-9 [17]

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3 years ago
A whole number n which when divided by 4 gives 3 as remainder. What will be the remainder when 2n is divided by 4?.
jeyben [28]

When 2n is divided by 4 the remainder will be 2

Division is a simple operation in which a number is divided.

Given,

A whole number n which when divided by 4 gives 3 as remainder

We know,

Dividend = (Divisor × quotient)+ Remainder

Here,

Dividend = n

Quotient = 4

Remainder =3

Consider the divisor as a

Then,

n = 4a+3

Multiply both side by 2

2n= 2(4a+3)

2n= 8a+6

Split the term 6 and take common outside

2n= 8a+4+2

2n= 4(2a+1)+2

So, when 2n is divided by 4

Divisor = 2a+1

Remainder = 2

Hence, when 2n is divided by 4 the remainder will be 2

Learn more about division here

brainly.com/question/21416852

#SPJ4

6 0
2 years ago
29. Which of the following expressions will result in a real answer after being simplified? Select all that apply.
nexus9112 [7]

Answer: A, B, C, and E

Step-by-step explanation:

If both sides are real numbers, then the product will be a real number.

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This is when:

Suppose we have a number:

z = a + b*i

The conjugate will be:

w = a - b*i

And the product between them is:

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Then the options that will have a real answer are:

A. (4+5i)(4-5i) = 4^2 + 5^2 = 16 + 25 = 41

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C. (3 + 2*i)*(3 -2*i) = 3^2 + 2^2 = 9 + 4 = 13

E. (312 + 7i)*(312 - 7i) = 312^2 + 7^2 = 97,393

5 0
3 years ago
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