√3 → irrational
-1/10 → rational
0 → rational
√2 → irrational
Evaluating an expression means either to solve the expressions or to simply it.
Solving an expression:
2 - (10 + 5)
A simply expression. After doing the math the answer comes out as -3.
2x + 3x
This is an algebraic expression. This means we have variables like x and y.
In this case, we can only simplify it. Because we don't know what x is equal to.
Because they are like terms (which means they have the variable) we can add them to together.
2x + 3x = 5x
I hope this answer clears up any misunderstandings about expressions and over all helped you learn something! If you still need some help, don't hesitate to DM on Brainly! I wish you best of luck on your journey of math!
EDIT:
Now what if you have an expression like this:
5x + 5m where x=4 and m=8
In mathematics, something like 5x is the same difference as 5 * x.
And x is just a placeholder for a number or for another variable.
And in this equation, x is equal to 4. So, we just replace x with 4.
5(4) + 5m
Same this with m. The variable m is equal to 8.
5(4) + 5(8)
We can solve!
5(4) + 5(8) = 20 + 40 = 60
Our answer is 60.
Answer:
C
Step-by-step explanation:
The mean of a data set is described as the sum of the data values divided by the total number of data values.
Answer:
1 and 2 are not congruent; 1 and 3 are congruent; 1 and 4 are congruent; 2 and 3 are not congruent; 2 and 4 are not congruent; 3 and 4 are congruent.
Step-by-step explanation:
From the diagram, we can see that the angle measures and side measures of figures 1, 3 and 4 are the same. This means that these three figures are congruent. Figure 2, however, is not congruent to any of the other 3.
Answer:
d. 15
Step-by-step explanation:
Putting the values in the shift 2 function
X1 + X2 ≥ 15
where x1= 13, and x2=2
13+12≥ 15
15≥ 15
At least 15 workers must be assigned to the shift 2.
The LP model questions require that the constraints are satisfied.
The constraint for the shift 2 is that the number of workers must be equal or greater than 15
This can be solved using other constraint functions e.g
Putting X4= 0 in
X1 + X4 ≥ 12
gives
X1 ≥ 12
Now Putting the value X1 ≥ 12 in shift 2 constraint
X1 + X2 ≥ 15
12+ 2≥ 15
14 ≥ 15
this does not satisfy the condition so this is wrong.
Now from
X2 + X3 ≥ 16
Putting X3= 14
X2 + 14 ≥ 16
gives
X2 ≥ 2
Putting these in the shift 2
X1 + X2 ≥ 15
13+2 ≥ 15
15 ≥ 15
Which gives the same result as above.
