3 years ago

Please help. Which section of the reaction represents the product?

Physics

1 answer:

lilavasa [31]3 years ago

8 0

C or b because they both have the same product

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Tor F: When you exert a force on a baseball, the equal and opposite force on the

Ratling [72]

The answer would be false

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3 years ago

estimate the force that a cyclist travelling at 6m/s needs to apply to the brakes to bring the bicycle to a stop in a distance o

RSB [31]

v1 = 6m/s

v2 = 0

∆v = v1 - v2 = 6m\s

s = t * v = 15m

t = s\v1 = 15(m) \ 6(m\s) = 2.5s

a = ∆v\t = 6(m\s) \ 2.5s = 2.4m\s2

a = F\m = 2.4m\s2

F = a * m = 2.4m\s2 * ?kg

I can't tell you this because I don't know the mass of this cyclist

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4 years ago

The wavelength of violet light is about 425 nm (1 nanometer = 1 × 10−9 m). what are the frequency and period of the light waves?

dexar [7]

1) Frequency: $7.06\cdot 10^{14} Hz$

The frequency of electromagnetic radiation is given by:

$f=\frac{c}{\lambda}$

where

$c = 3 \cdot 10^8 m/s$ is the speed of light

$\lambda$ is the wavelength

In this case, the wavelength of the radiation is

$\lambda=425 nm=425\cdot 10^{-9} m$

Therefore the frequency is

$f=\frac{3\cdot 10^8 m/s}{425 \cdot 10^{-9} m}=7.06\cdot 10^{14} Hz$

2) Period: $1.42\cdot 10^{-15} s$

The period is equal to the reciprocal of the frequency of the wave:

$T=\frac{1}{f}$

Using the frequency we found previously, $f=7.06\cdot 10^{14} Hz$ , we find:

$T=\frac{1}{7.06\cdot 10^{14} Hz}=1.42\cdot 10^{-15} s$

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4 years ago

Find the speed of a bicyclist who took an hour and a half to travel 10km

Natalija [7]

distance = 10km

time = 1 1/2 = 3/2 hours

speed = distance/time = 10 / 3/2 = 20/3 = 6.67 Km/h

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3 years ago

A 59 kg block is positioned 2.0 meters away from another 59 kg block. What is the gravitational force exerted on each object?

Natali [406]

Answer:

Explanation:

The gravitational force equation is

$F_g=\frac{Gm_1m_2}{r^2}$ where G is the gravitational constant. Filling in with what we are given and what we know to be true:

$F_g=\frac{6.67*10^{-11}(59)(59)}{(2.0)^2}$ which, when you do the math, comes out to be

$F_g=5.8*10^{-8}N$ , choice A.

4 0

3 years ago