What is the work function of cadmium metal if light with = 9.85×1014hz is necessary to eject electrons?

Physics

1 answer:

Alika [10]3 years ago

3 0

We use the Planck’s formula:

E = hv

where,

E = energy, h = planck’s constant = 6.6x10^-34 J s, v = frequency in Hz (Hz = 1 / s)

Subsituting the values to find for E:

E = (6.6×10^-34 J s) * 9.85×10^14 / s

E = 6.5x10^-19 J

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