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Sergio [31]
3 years ago
5

What are the first five terms of the sequence defined by the given function?

Mathematics
1 answer:
kenny6666 [7]3 years ago
8 0

Answer: B. -6, -4, -2, 0, 2

Step-by-step explanation: Use the attachment to help you with your answer.

Anyways, have an amazing day!

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Simplify to create an equivalent expression.<br> 8(a+2)+2(2+3a)=
Alchen [17]

Answer:

14a + 20

Step-by-step explanation:

8(a + 2) + 2(2 + 3a)

expand the bracket

8a + (8*2) + (2*2) + (2*3a)

8a + 16 + 4 + 6a

bring like terms together

8a + 6a + 16 + 4

14a + 20

3 0
3 years ago
If a girl cuts the grass in 3 hours and a boy cuts it in 2 hours what would be the time if they cut it toghther.?
svet-max [94.6K]

Answer:

d

Step-by-step explanation:

the answer is d because if you do 3+2 it equals 5 so therefore it is b

4 0
3 years ago
Read 2 more answers
Question 1:
Dominik [7]
14+2x=62        (x=Pass cost)
-14        -14
(2x=48)/2
x=24

6.50+5.75+1.15x=18
12.25+1.15x=18
-12.25          -12.25
1.15x=5.75 divide both sides by 1.15
x=5

5 0
3 years ago
-5 +8 + (9) =<br> What is the answer for the following equestion
AlexFokin [52]

Answer:

12

Step-by-step explanation:

So we use PEMDAS:

-5 + 8 = 3

3 + 9 = 12

4 0
3 years ago
Read 2 more answers
Please help! For the function f(x) = 2x^6 + 3x^4 - 4x^3 + (1/x) - sin(2x) find the first four derivatives.
klasskru [66]

Answer:

See the explanation

Step-by-step explanation:

We know that

f(x) = 2x⁶ + 3x⁴ - 4x³ + (1/x) - sin2x

Lets calculate the derivatives:

f'(x) = 6(2x⁵) + 4(3x³) - 3(4x²) -( 1/x²) - 2(cos2x)

f'(x) = 12x⁵ + 12x³ - 12x² - (1/x²) - 2cos2x

Similarly:

f''(x) = 60x⁴ + 36x² - 24x + (2/x³) + 4sin2x

f'''(x) = 240x³ + 72x - 24 - (6/x⁴) + 8cos2x

Rearrange:

f'''(x) - 240x³ +72x - (6/x⁴) + 8cos2x - 24

f''''(x) = 720x² + 72 + (24/x⁵) - 16sin2x

Rearrange:

f''''(x) = 720x² + (24/x⁵) - 16sin2x +72

8 0
3 years ago
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