Answer:
Mass of B-11 = 11.009 amu
Explanation:
Given data:
Abundance of B-10 = 19.9%
Abundance of B-11 = 80.1%
Mass of B-10 = 10.013 amu
Mass of B-11 = ?
Solution:
Average atomic mass of boron is 10.811 amu.
Average atomic mass of boron = (abundance of 1st isotope × its atomic mass) +(abundance of 2nd isotope × its atomic mass) / 100
10.811 = (10.013×19.9) + (x × 80.1) /100
10.811 = 199.26 + (x × 80.1)
10.811 × 100 = 199.26 + (x × 80.1)
1081.1- 199.26 = x × 80.1
881.84 = x × 80.1
881.84/ 80.1 = x
x = 11.009
Anything that can be measured in meters.
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Answer:
i. The height of its jump is approximately 0.115 m
ii. The time of flight of its jump is approximately 0.306 seconds
iii. The range of its jump is approximately 0.795 m
Explanation:
The angle at which the grasshopper jumps, θ = 30°
The speed with which the grasshopper takes off, u = 3 m/s
i. The height of its jump 'h', is given by the following relation;
Where;
g = The acceleration due to gravity ≈ 9.81 m/s²
Therefore;
The height of its jump, h ≈ 0.115 m
ii. The time of flight of its jump, 't', is given as follows;
Therefore;
The time of flight of its jump, t ≈ 0.306 seconds
iii. The range of the jump is given by the following projectile motion equation for the range as follows;
Therefore;
The range of the jump, R ≈ 0.795 m.