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3 years ago

F(x) = x2 - 1 r the number that belongs in the gree x = -1; x = [?]

Mathematics

1 answer:

grandymaker [24]3 years ago

5 0

Bsbdhdnabsndnsnandjdns sbfj

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20 points 3 math questions please help with these math questions

JulsSmile [24]

Answer:

B, False,

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

What is the coefficient of (-2/3x)(3y)(-2x)

dolphi86 [110]

Answer:

The coefficient is equal to $4$

Step-by-step explanation:

we have

$(-\frac{2}{3}x)(3y)(-2x)$

we know that

The coefficient is equal to

$(-\frac{2}{3})(3)(-2)=4$

$(-\frac{2}{3}x)(3y)(-2x)=4x^{2}y$

4 0

3 years ago

A. -7x+5 B. -7x-35 C. -7x+35 D. x-35

liubo4ka [24]

Answer:

Step-by-step explanation:

p(x) = r(x) * s(x)

= (x + 5) *(-7) {Use distributive property}

= x * -7 + 5 * -7

= - 7x - 35

5 0

4 years ago

Read 2 more answers

HEEELP

Drupady [299]

Answer: (c)

Step-by-step explanation:

Given

$f(x)=\dfrac{1}{x-3}\\\\g(x)=\sqrt{x+5}$

Here, $\sqrt{x+5}\ \text{is always greater than equal to 0}\\\Rightarrow x+5\geq 0\\\Rightarrow x\geq -5\quad \ldots(i)$

To get $f\left(g(x)\right)$ , replace $x$ in $f(x)$ by $g(x)\ \text{i.e. by}\ \sqrt{x+5}$

$\Rightarrow f\left(g(x)\right)=\dfrac{1}{\sqrt{x+5}-3}\\\\\text{Denominator must not be equal to 0}\\\\\therefore \sqrt{x+5}-3\neq0\\\Rightarrow \sqrt{x+5}\neq 3\\\Rightarrow x+5\neq 9\\\Rightarrow x\neq 4\quad \ldots(ii)$

Using $(i)$ and $(ii)$ it can be concluded that the domain of $f\left(g(x)\right)$ is all real numbers except 0.

Therefore, its domain is given by

$x\in [-5,4)\cup (4,\infty)$

Option (c) is correct.

5 0

3 years ago

(-4, 8) and (6, 2). Slope

Setler79 [48]

Answer:

In order to go from the first point to the second, we need to rise from 4 to 7, i.e. by 3. We also need to run from -4 to -2, i.e. by 2. Therefore the slope is 32 .

Step-by-step explanation:

8 0

2 years ago

F(x) = x2 - 1 r the number that belongs in the gree x = -1; x = [?]​

F(x) = x2 - 1 r the number that belongs in the gree x = -1; x = [?]