Answer:
D option is correct
( At Q3 the market is wasting society's .. )
I'll do the first one to get you started
The equation y = x^2+16x+64 is the same as y = 1x^2+16x+64
Compare that to y = ax^2+bx+c and we see that
a = 1
b = 16
c = 64
Use the values of 'a' and b to get the value of h as shown below
h = -b/(2a)
h = -16/(2*1)
h = -8
This is the x coordinate of the vertex.
Plug this x value into the original equation to find the corresponding y value of the vertex.
y = x^2+16x+64
y = (-8)^2 + 16(-8) + 64
y = 0
Since the y coordinate of the vertex is 0, this means k = 0.
The vertex is (h,k) = (-8, 0)
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So we found that a = 1, h = -8 and k = 0
Therefore,
f(x) = a(x-h)^2 + k
f(x) = 1(x-(-8))^2 + 0
f(x) = (x+8)^2
is the vertex form
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<h3>Final answer to problem 1 is f(x) = (x+8)^2 </h3>
Answer:
i can send you questions of class 8
Answer:
width = 12 ft
Step-by-step explanation:
Given the figure of the pond and the fact that the corners form a right triangle that is across from the string of flags, you can use the Pythagorean Theorem to solve for the width of the triangle that is formed by the flags:
a² + b² = c², where 'a' and 'b' represent the legs of the triangle and 'c' represents the diagonal or hypotenuse. Using 16 for 'a' and 20 for 'c':
16² + b² = 20²
256 + b² = 400
Subtract 256 from both sides: 256 - 256 + b² = 400 - 256 or b² = 144
Take the square root of both sides: √b² = √144 or b = 12 ft
Answer:
She is not correct because she did not substitute the same number in both expressions in Step 1
Step-by-step explanation:
CASE 1: substitute 1 for x to both sides of the equations
L.H.S
-(4x-5)+2(x-3)
-(4 (1) - 5)+ 2(1-3) = - (-1) + 2(-2) = 1 - 4 = -3
R.H.S
-2x - 5
-2(1) - 5 = -2-5 = -7
Hence for x= 1
-(4x-5)+2(x-3) ≠ -2x -5
Because -3 ≠ -7
CASE 2: substitute -1 for x to both sides of the equations
L.H.S
-(4x-5)+2(x-3)
-(4 (-1) - 5)+ 2(-1-3) = - (-9) + 2(-4) = 9 - 8 = 1
R.H.S
-2x - 5
-2(-1) - 5 = 2-5 = -3
Hence for x= -1
-(4x-5)+2(x-3) ≠ -2x -5
Because 1 ≠ -3
Answer:
She is not correct because she did not substitute the same number in both expressions in Step 1
