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adelina 88 [10]
3 years ago
10

Evaluate log 2 base 8​

Mathematics
1 answer:
iren2701 [21]3 years ago
3 0

Answer:  The correct answer is:  " 3 " .

_______________________________

Step-by-step explanation:

_______________________________

The problem given is:

_______________________________

Evaluate:  log 2 base 8 .

_______________________________

Rewrite as:  " log_2}8 = ? _______________  " ;  log_2}8 = ? _______________

_______________________

Take note of the following definition of a logarithm:

_______________________

"   log_{m}n = a " ;  ↔  " m^{a} =n  "  ;

_______________________

in which:  m  refers to the "base" ;

               n  refers to the "argument" ;

               a  refers to the "exponent" ;

______________________________

As such:

       " log_2}8 = ? _______________ "

      ⇔ " 2^{x} = 8 " ; Solve for "x" ;  

 _______________

 Note:  

  2⁰ = 1 ;

  2¹ = 2 ;

  2² = 2 * 2 = 4 ;

  2³ = 2 * 2 * 2 = 8 .

___________________

 → " 2^{x} = 8 " ;

 → " 2^{3} = 8 " ;  since: " 2^{3} = 2  *2 *2 = 8 " ;

 → as such:   " x = 3  " ;

______________________

Thus:

"log 2 base 8 " ;

          = log{_{2}}8 = 3  .

_______________________

Hope this helps!

Best wishes to you!

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Answer:

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3 years ago
7. In the accompanying diagram of rhombus CDEF, diagonal FD is drawn and the
tatiyna

Answer:

m∠CFD is 70°

Step-by-step explanation:

In the rhombus

  • Diagonals bisect the vertex angles
  • Every two adjacent angles are supplementary (their sum 180°)

Let us solve the question

∵ CDEF is a rhombus

∵ ∠E and ∠F are adjacent angles

→ By using the second property above

∴ ∠E and ∠F are supplementary

∵ The sum of the measures of the supplementary angles is 180°

∴ m∠E + m∠F = 180°

∵ m∠E = 40°

∴ 40° + m∠F = 180°

→ Subtract 40 from both sides

∵ 40 - 40 + m∠F = 180 - 40

∴ m∠F = 140°

∵ FD is a diagonal of the rhombus

→ By using the first property above

∴ FD bisects ∠F

→ That means FD divides ∠F into 2 equal angles

∴ m∠CFD = m∠EFD = \frac{1}{2} m∠F

∴ m∠CFD = \frac{1}{2} (140°)

∴ m∠CFD = 70°

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What is the strongest classification of the figure formed by the following points?
tatiyna

Answer:

A. Parallelogram

Step-by-step explanation:

The given points are;

(-10, -4), (-7, -8), (-5, -4), (-2, -8)

Let 'A' represent the point (-10, -4), let 'B' represent the point (-7, -8), let 'C' represent the point (-5, -4), and let 'D' represent the point (-2, -8), we have;

The (horizontal) distance between points A and C = -5 - (-10) = 5

The (horizontal) distance between points B and D = -2 - (-7) = 5

Therefore;

The length of \overline {AC} = The length of \overline {BD}

The length of \overline {AB} = √((-10 - (-7))² + (-4 - (-8))²)) = 5

The length of \overline {CD} = √((-5 - (-2))² + (-4 - (-8))²)) = 5

∴ The length of \overline {AB} = The length of \overline {CD}

\overline {AC} is parallel to the horizontal axis

\overline {BD} is parallel to the horizontal axis

∴ \overline {AC} ║ \overline {BD}

Given that \overline {AB} = \overline {CD}, then \overline {AB} ║ \overline {CD}

Therefore, the quadrilateral ABCD is a parallelogram

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