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inysia [295]
2 years ago
11

A popular photo editing application provides customers with the option of accessing a web based version through a monthly subscr

iption
Computers and Technology
1 answer:
Black_prince [1.1K]2 years ago
6 0

Answer:

photoshop app that purchase with a lower price 3$ per month

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A standard is something that is always at a certain time of the day and is scheduled the same. A protocol takes priority of anything and everything else you work on.
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Given two 2x3 (2 rows, 3 columns) arrays of integer , x1 and x2, both already initialized , two integer variables , i and j, and
Gnesinka [82]
JAVA programming was employed...

What we have so far:
* Two 2x3 (2 rows and 3 columns) arrays. x1[i][j] (first 2x3 array) and x2[i][j] (second 2x3 array) .
* Let i = row and j = coulumn.
* A boolean vaiable, x1rules

Solution:

for(int i=0; i<2; i++)
{
   for(int j=0; j<3; j++)
   {
      x1[i][j] = num.nextInt();
   }
}// End of Array 1, x1.

for(int i=0; i<2; i++)
{
   for(int j=0; j<3; j++)
   {
      x2[i][j] = num.nextInt();
   }
}//End of Array 2, x2
This should check if all the elements in x1 is greater than x2:

x1rules = false;
if(x1[0][0]>x2[0][0] && x1[0][1]>x2[0][1] && x1[0][2]>x2[0][2] && x1[1][0]>x2[1][0] && x1[1][1]>x2[1][1] && x1[1][2]>x2[1][2])
{
   x1rules = true;
   system.out.print(x1rules);
}
else
{
   system.out.print(x1rules);
}//Conditional Statement
7 0
3 years ago
Consider the following code:
Phoenix [80]

Answer:

customers += newCustomer;

Explanation:

The operator += expands into + and assignment. The assignment is not overloaded so the required code is

customers += newCustomer;

This expands into

customers = customers + newCustomer;

The overloaded + operator is called for the right expression. This returns a `CustomerList`, which is then assigned through the = operator to `customers`.

3 0
3 years ago
Write an if statement that tests to see whether a String stored in a variable named phrase begins with a capital letter. If the
mamaluj [8]

Answer & Explanation:

//written in java

public class Main {

   public static void main(String[] args) {

       //String stored in a variable named phrase

       String phrase = "Brainly";

       //Checking whether the first character is in upper case or not

       if (Character.isUpperCase(phrase.charAt(0)))

           System.out.println("capital");

       else

           System.out.println("not capital");

   }

}

4 0
3 years ago
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