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IgorC [24]
3 years ago
6

What are the first three terms of the Arithmetic Sequence an = 11 – 3(n – 1)?

Mathematics
1 answer:
vaieri [72.5K]3 years ago
3 0

Answer:First three terms: 11,20,29 .

Step-by-step explanation:

Write a systems of equations. tn=a+(n−1)d. sn=n2 (2a+(n−1)d). So,. 110=11+(n−1)d 726=n2(22+(n−1)d).

I hope this is right

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Help??<br> anyone?<br> 7th grade math <br> tysm
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Please help me out with this
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Answer:

374.1

Step-by-step explanation:

Area of Hexagon = \frac{3\sqrt{3} }{2} * a^{2}

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3 years ago
Increase 250ml by 86%
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6 0
3 years ago
Please solve the following sum or difference identity.
xxTIMURxx [149]

Answer:

sin(A - B) = \frac{4}{5}

Step-by-step explanation:

Given:

sin(A) = \frac{24}{25}

sin(B) = -\frac{4}{5}

Need:

sin(A - B)

First, let's look at the identities:

sum: sin(A + B) = sinAcosB + cosAsinB

difference: sin(A - B) = sinAcosB - cosAsinB

The question asks to find sin(A - B); therefore, we need to use the difference identity.

Based on the given information (value and quadrant), we can draw reference triangles to find the simplified values of A and B.

sin(A) = \frac{24}{25}

cos(A) = \frac{7}{25}

sin(B) = -\frac{4}{5}

cos(B) = \frac{3}{5}

Plug these values into the difference identity formula.

sin(A - B) = sinAcosB - cosAsinB

sin(A - B) = (\frac{24}{25})(\frac{3}{5}) - (-\frac{4}{5})(\frac{7}{25})

Multiply.

sin(A - B) = (\frac{72}{125}) + (\frac{28}{125})

Add.

sin(A - B) = \frac{4}{5}

This is your answer.

Hope this helps!

6 0
3 years ago
Read 2 more answers
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