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pantera1 [17]
3 years ago
9

1. Una carga eléctrica de 5*10-6 C genera un campo eléctrico a su alrededor. Calcula la intensidad de este campo a una distancia

de 0, 8 m
Physics
1 answer:
Jlenok [28]3 years ago
5 0

Answer:

La intensidad del campo eléctrico es 70312.5 \frac{N}{C}.

Explanation:

La perturbación que crea en torno a ella una carga eléctrica se representa mediante un vector denominado campo eléctrico.

Se dice que un campo eléctrico es uniforme en una región del espacio cuando la intensidad de dicho campo eléctrico es el mismo en todos los puntos de dicha región.

El campo eléctrico E creado por la carga puntual q en un punto cualquiera P se define como:

E=k*\frac{q}{r^{2} }

donde q es la carga creadora del campo, k es la constante electrostática y r es la distancia desde la carga fuente al punto P.

En este caso, los datos son:

  • k= 9*10⁹ \frac{N*m^{2} }{C^{2} }
  • q= 5*10⁻⁶ C
  • r= 0.8 m

Reemplazando:

E=9*10^{9}\frac{N*m^{2} }{C^{2} }  *\frac{5*10^{-6} C}{(0.8 m)^{2} }

Resolviendo:

E= 70312.5 \frac{N}{C}

<em><u>La intensidad del campo eléctrico es 70312.5 </u></em>\frac{N}{C}<em><u>.</u></em>

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Answer:

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Explanation:

The question relates to the force of gravity experienced between two bodies

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By Newton's Law of gravitation, we have;

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By plugging in the values of the parameters and the constant into the equation for Newton's Law of gravitation, we have;

F=6.67430 \times 10^{-11} \times \dfrac{1 \times 10^8 \times 1 \times 10^9}{(5,000,000)^{2}} = 2.66972 \times 10^{-7}

The force, 'F', exerted by Big Ben on the Empire State Building is F = 2.66972 × 10⁻⁷ N.

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Answer:

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