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Nat2105 [25]
3 years ago
14

Which Box in the diagram above, should this picture go into?

Physics
1 answer:
lyudmila [28]3 years ago
7 0
What diagram? There isn’t one
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Define the term “force”.
Aleonysh [2.5K]

Energy that is applied to an object.

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Where would you weigh the most?
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What is the frequency, in units of kiloHertz, of an AC waveform that has a period of 12 microseconds?
Alik [6]

Answer:

83.3 kHz

Explanation:

The frequency of a waveform is equal to the reciprocal of its period:

f=\frac{1}{T}

where

f is the frequency

T is the period

In this problem, we have

T=12 \mu s=12\cdot 10^{-6} s

so, the frequency of the waveform is

f=\frac{1}{12 \cdot 10^{-6} s}=8.33\cdot 10^4 Hz

And by converting into kiloHertz,

f=8.33\cdot 10^4 Hz=83.3 kHz

3 0
3 years ago
1. Compare the speed that light waves travel in air to the speed that sound waves travel in the air. How many times faster do li
Vladimir79 [104]

Answer:

895522 times faster.

Explanation:

From the question given above, the following data were obtained:

Speed of sound in air (v) = 335 m/s

Speed of light in air (c) = 3×10⁸ m/s

How many times faster =.?

To obtain how many times faster light travels in air than sound, do the following

c : v => 3×10⁸ : 335

c/v = 3×10⁸ / 335

c/v = 895522

Cross multiply

c = 895522 × v

From the illustrations made above, we can see that the speed of the light in air (c) is 895522 times the speed of sound in air.

Thus, light travels 895522 times faster than sound in air.

6 0
2 years ago
in this model, the velocity of the spacecraft at position 2 is A.) equal to B.) greater than C.) less than the velocity of the c
finlep [7]
<h2>1. Right answer: the velocity of the spacecraft at position 2 is <u>greater than</u> the velocity of the craft at position 4. </h2>

This is due the gravity field of the planet (The Earth in this case) is used to accelerate the craft. This is true when in a specific point the direction of the movement of the craft is the same direction of the movement of the planet.

In this case the craft will be “catched” by the Earth’s gravitational field, making the craft  to enter a circular orbit.

<h2>2. Right answer: At position 1, the direction of the spacecraft changes because of <u>the gravitational force between Earth and the spacecraft. </u></h2>

As explained in the prior answer, this is the exact and correct point where the trajectory of the spacecraft enters into a circular orbit because of the attraction due gravity of the Earth and therefore changes its direction.


<h2>3. Right answer: Position 3 represents <u>the orbital path or velocity of Earth </u></h2>

Being this the orbital path of the Earth and considering the trajectory of the craft, the condition of accelerating the craft is accomplished.

If the orbital path of the Earth were the opposite from the shown in the figure, the effect on the craft would be braking.

Note all of these is related to the <u>gravitational assistance. </u>

<u>Gravitational assistance</u> is the maneuver in which the energy of the gravitational field of a planet or satellite is used to obtain an acceleration or braking of the probe changing its trajectory.

This maneuver is also called <em>slingshot effect, swing-by</em> or <em>gravity assist</em>. It is a common technique in space for the outer Solar System missions , in order to save costs in the launch rocket and thrusters.


6 0
3 years ago
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