What is the pulling force of this train, if its engine provides 4200 kW power and 90 km/h speed?

what is the wavelength of light (in nanometers) that has a frequency of 1.75 x 1013 hz? the speed of light is 3.00 x 108 m/s.

Leokris [45]

The light has a frequency of 1.75 x 10¹³ hz. The speed of light is 3.00 x 10⁸ m/s. The wavelength of light is (λ) = 1.714 x 10⁴ nm

<h3>What is wavelength?</h3>

When a wave that propagates in a medium it has different lengths. That length of the wave is called the wavelength. It can be measured in m, cm, nm etc.

<h3>How can we calculate the wavelength?</h3>

To calculate the wavelength we are using the formula,

λ=c/f

Here we are given,

c= The speed of light in zero space. = 3.00 x 10⁸ m/s.

f = The frequency of the light. = 1.75 x 10¹³ hz.

We have to calculate the wavelength of the light = λ m

Now we put the values in above equation we get,

λ=c/f

Or, λ=3.00 x 10⁸ / 1.75 x 10¹³

Or, λ= 1.714 x 10⁻⁵ m

So we can easily say that,

The wavelength of light is (λ) =1.714 x 10⁻⁵ m = 1.714 x 10⁴ nm

Learn more about wavelength:

brainly.com/question/10728818

#SPJ4

5 0

1 year ago

If a 3-kg object has a momentum of 33 kg·m/s, what's its velocity?

kramer

Its velocity is 11 m/s.

5 0

4 years ago

A simple model of a hydrogen atom is a positive point charge +e (representing the proton) at the center of a ring of radius a wi

Norma-Jean [14]

Answer:

Now e is due to the ring at a

So

We say

1/4πEo(ea/ a²+a²)^3/2

= 1/4πEo ea/2√2a³

So here E is faced towards the ring

Next is E due to a point at the centre

So

E² = 1/4πEo ( e/a²)

Finally we get the total

Et= E²-E

= e/4πEo(2√2-1/2√2)

So the direction here is away from the ring

8 0

4 years ago

In a physics experiment, two equal-mass carts roll towards each other on a level, low-friction track. One cart rolls rightward a

xz_007 [3.2K]

Answer:

The correct answer is option a.

Explanation:

Conservation of momentum :

$m_1u_1+m_2u_2=m_1v_1+m_1v_2$

Where :

$m_1, m_2$ = masses of object collided

$u_1,u_2$ = initial velocity before collision

$v_1,v_2$ = final velocity after collision

We have :

Two equal-mass carts roll towards each other.

$m_1=m_2=M$

Initial velocity of $m_1=u_1=2 m/s$

Initial velocity of $m_2=u_2=-1 m/s$ (opposite direction)

Final velocity of $m_1=v_1=v$ (same direction )

Final velocity of $m_2=v_2=v$ (same direction)

$M\times 2 m/s+M(-1 m/s)=Mv+Mv$

$1 m/s=2v$

v = 0.5 m/s

rg135

The speed of the carts after their collision is 0.5 m/s.

7 0

4 years ago

Explain what voltage,current, resistance are and how they relate to Ohms law. Then give examples

SOVA2 [1]

Voltage is the difference in charge between two points.
Current is the rate the charge flows
Resistance is the tendency a material has to resist the flow of charge (current)
Combining voltage resistance and current Ohm developed the formula
V (Voltage)= I (Current) x R (Resistance)

3 0

4 years ago