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Vanyuwa [196]
3 years ago
7

Suppose that you buy a two-year 7.4% bond at its face value. a-1. What will be your total nominal return over the two years if i

nflation is 2.4% in the first year and 4.4% in the second?
Business
1 answer:
Harman [31]3 years ago
8 0

Answer: 15.35%

Explanation:

The total nominal return over the two years if inflation is 2.4% in the first year and 4.4% in the second year will be calculated thus:

= (1+Interest rate)² -1

= (1 + 7.4%) - 1

= (1 + 0.074)² - 1

= 1.074² - 1

= 1.153476 - 1

= 0.153476

= 15.35% over the two years

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The difference between the monthly payment of R and S is equal to $48.53 by following the compound interest formula. Thus, Loan R's monthly loan amount is greater than Loan S.

<h3>What is a Compound interest loan?</h3>

Combined interest (or compound interest) is the loan interest or deposit calculated based on both the original interest and accrued interest from earlier periods.

\rm\,For\,R\\\\P = \$\,17,550\\r\,= 5.32\%\\Time\,= n= 7\,years\\Amount\,paid= [P(1+\dfrac{r}{100\times12})^{n\times12} ]\\=[ 17,550 (1+\dfrac{5.32}{100\times12})^{7\times12} ]\\= [ 17,550 (\dfrac{12.0532}{12})^{84} ]\\\\=  [ 17,550 (1.00443^{84} ]\\\\= \$ 25,440.48\\\\Total\,monthly\,payment = \rm\,\dfrac{25,440.48}{84}\\\\= \$\, $302.86\\\\

\rm\,For\,S =\\\\P=\,\$ 15,925\\r\,= 6.07\%\\T=n= 9\,years\\\\Amount\,paid\,= [P(1+\dfrac{r}{100\times12})^{n\times12} ]\\\\\= [15,925(1+\dfrac{0.0607}{12})^{9\times12} ]\\\\\\= [15,925(1+\dfrac{0.0607}{12})^{108} ]\\\\=[15,925(1.7247.84)} ]\\\\\= \$27,467.19\\\\Total\,monthly\,payment =\dfrac{\rm\,\$\,27,469.19}{108}\\\\= \$ 254.326\\\\

The difference between the monthly payment of R and S is equal to $48.53.

Hence, Loan R's monthly payment is greater than the loan's monthly payment by $48.53

To learn more about Compound interest, refer to the link:

brainly.com/question/14331235

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