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laiz [17]
3 years ago
15

.Here is a 90% confidence interval estimate of theproportion of adults who say that thelaw goes easy on celebrities: 0.645

Mathematics
1 answer:
bulgar [2K]3 years ago
5 0

Answer:

The best estimate of the proportion of adults who say that the law goes easy on celebrities is 0.7435.

Step-by-step explanation:

Confidence interval concepts:

A confidence interval has two bounds, a lower bound and an upper bound.

A confidence interval is symmetric, which means that the point estimate used is the mid point between these two bounds, that is, the mean of the two bounds.

In this question:

CI is between 0.645 and 0.842. So the best estimate of the proportion is:

(0.645+0.842)/2 = 0.7435

The best estimate of the proportion of adults who say that the law goes easy on celebrities is 0.7435.

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(8x² + 3x) - 4x² + x-4
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Number 2 I need help on how to solve it
Hunter-Best [27]

Let's simplify the following expression:

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We get,

\text{ }\frac{(\text{2x}^4\text{ - y}^6\text{z}^{-4})^2}{\text{ 2x}^2\text{z}^3}\text{ }\cdot\text{  }\frac{6x^5y^{-4}z^{-5}}{(2x^6y^3z^{-3})^2}\text{ }\frac{(2x^4-y^6z^{-4})^2(6x^5y^{-4}z^{-5})}{(2x^2z^3)(2x^6y^3z^{-3})^2}\text{ }\frac{(4x^8\text{ - 4x}^4y^6z^{-4}\text{ + y}^{12}z^{-8})(6x^5y^{-4}z^{-5})}{(2x^2z^3)(4x^{12}y^6z^{-6})}\text{ }\frac{24x^{13}y^{-4}z^{-5}\text{ - 24x}^9y^2z^{-9}\text{ + 6x}^5y^8z^{-13}}{8x^{14}y^6z^{-3}}

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Step-by-step explanation:

because 1 page=$0.70 and now calculate

10×1×0.70=7

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2 years ago
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