3 years ago

Wqolsak,fdsf nlkdsflksfksdjfkdsfjslkdafj

1 answer:

4 0

Answer:

ksnbdndk djdbnsjsksk djdjjsksks ksksj dndjjdjsjsjkskdkd

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muminat

Answer:

Step-by-step explanation:

Given that A is a square matrix and A is idempotent

$A^2 = A$

Consider I-A

i) $(I-A)^2 = (I-A).(I-A)\\= I^2 -2A.I+A^2\\= I-2A+A\\=I-A$

It follows that I-A is also idempotent

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So it follows that 2A-I matrix is its own inverse.

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