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3 years ago

The solutions to the equation 2x^2 + x - 1 = 2 are x = -3/2 or x = _______.

Mathematics

1 answer:

garik1379 [7]3 years ago

4 0

Answer:

The remaining solution to the equation is x = 1

Step-by-step explanation:

2x^2 + x - 1 = 2

First set the equation to zero by subtracting 2 from each side:

2x^2 + x - 1 - 2 = 2 - 2

2x^2 + x - 3 = 0

Factor the left side of the equation:

2x^2 + x - 3 = 0

(2x + 3)(x - 1) = 0

Now set each factor to zero and solve:

2x+ 3 = 0

2x+ 3 - 3 = 0 - 3

2x= -3

2x/2= -3/2

x= -3/2 (The given expression)

x - 1 = 0

x - 1 + 1 = 0 + 1

x = 1

Since we already knew x = -3/2, the missing solution is x = 1.

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Since our function is A(L)=640L-2L², we get

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plug in the value of a and b into the first formula:

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