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2 years ago

What's the operation for 2(t+1)=10

Mathematics

1 answer:

fiasKO [112]2 years ago

3 0

The answer is t=4 hope it right

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Nathan read 2 books in 10 months. What was his rate of reading in books per month

Novay_Z [31]

<h2>Answer:</h2><h2>The rate of reading a book per month = $\frac{1}{5}$ = 20%</h2>

Step-by-step explanation:

Nathan read 2 books in 10 months.

The time taken to complete 1 book = $\frac{10}{2}$ = 5 months

To complete 1 book it takes 5 months.

The rate of reading a book per month = $\frac{1}{5}$ = 20%

4 0

3 years ago

<img src="https://tex.z-dn.net/?f=Simplify%3A%20%5Cfrac%7B%205%C3%97%2825%29%5E%7Bn%2B1%7D%20-%2025%20%C3%97%20%285%29%5E%7B2n%7

Katen [24]

$\green{\large\underline{\sf{Solution-}}}$

<u>Given expression is </u>

$\rm :\longmapsto\:\dfrac{5 \times {25}^{n + 1} - 25 \times {5}^{2n} }{5 \times {5}^{2n + 3} - {25}^{n + 1} }$

can be rewritten as

$\rm \: = \: \dfrac{5 \times { {(5}^{2} )}^{n + 1} - {5}^{2} \times {5}^{2n} }{5 \times {5}^{2n + 3} - {( {5}^{2} )}^{n + 1} }$

We know,

$\purple{\rm :\longmapsto\:\boxed{\tt{ {( {x}^{m} )}^{n} \: = \: {x}^{mn}}}} \\$

And

$\purple{\rm :\longmapsto\:\boxed{\tt{ \: \: {x}^{m} \times {x}^{n} = {x}^{m + n} \: }}} \\$

So, using this identity, we

$\rm \: = \: \dfrac{5 \times {5}^{2n + 2} - {5}^{2n + 2} }{{5}^{2n + 3 + 1} - {5}^{2n + 2} }$

$\rm \: = \: \dfrac{{5}^{2n + 2 + 1} - {5}^{2n + 2} }{{5}^{2n + 4} - {5}^{2n + 2} }$

can be further rewritten as

$\rm \: = \: \dfrac{{5}^{2n + 2 + 1} - {5}^{2n + 2} }{{5}^{2n + 2 + 2} - {5}^{2n + 2} }$

$\rm \: = \: \dfrac{ {5}^{2n + 2} (5 - 1)}{ {5}^{2n + 2} ( {5}^{2} - 1)}$

$\rm \: = \: \dfrac{4}{25 - 1}$

$\rm \: = \: \dfrac{4}{24}$

$\rm \: = \: \dfrac{1}{6}$

<u>Hence, </u>

$\rm :\longmapsto\:\boxed{\tt{ \dfrac{5 \times {25}^{n + 1} - 25 \times {5}^{2n} }{5 \times {5}^{2n + 3} - {25}^{n + 1} } = \frac{1}{6} }}$

4 0

2 years ago

Evaluate<img src="https://tex.z-dn.net/?f=10%5E%7B6%7D" id="TexFormula1" title="10^{6}" alt="10^{6}" align="absmiddle" class="la

katovenus [111]

121,000,000,000
this is because:
10^6= 1,000,000
10^3= 1,000
121^1= 121

3 0

2 years ago

A man weighs 180 lb. He jogs a mile in 8 minutes. How many calories has he used up?

s2008m [1.1K]

Calories used = Activity level*Weight*Duration

Activity level at 8 min/mile = 0.22 calories per minute
Weight = 180/2.2 = 81.81 kg
Duration = 8 minutes

Substituting;
Calories used = 0.22*81.81*8 = 144 calories

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2 years ago

If 3 people share 4 cookies equally how many cookies will they get

melamori03 [73]

Answer:

1.33333333

Step-by-step explanation:

3 0

2 years ago

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