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zzz [600]
3 years ago
12

If i had 2 cats and my mom bought me 4 dogs how many animals is that in total​

Mathematics
1 answer:
pashok25 [27]3 years ago
5 0

Answer:

2 cats + 4 dogs = 6 animals in total.

:)

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PLEASE HELP..... I WILL GIVE BRAINLIEST!!
Yakvenalex [24]
For the first part:

Every shirt she grabs, will cost her dollars, so if she grabs 3 shirts, then the cost of the shirts is:

12+12+12=3(12)

With the same rationale, if she grabs 2 pairs of jeans, the cost of the jeans is:

19+19=2(19)

So, her total is:

3(12)+2(19)

If you subtract 3 from the total, then the expression is:

3(12)+2(19)-3=36+38-3=71

For the second part:

If she's paying 3 less for each shirt, then the cost of 3 shirts will become:

(12-3)+(12-3)+(12-3)=3(12-3)

In the same fashion, for the two jeans:

(19-3)+(19-3)=2(19-3)

So the expression for the total cost is:

3(12-3)+2(19-3)=36-9+38-6=59

For number three:

The amounts are different because the cost of the total purchase is different than the cost of each element that makes up the total purchase.

For number four:

If you're the owner, you want to give the smallest amount of discount (the one in part 1/a).

So you could clarify by saying there's 3 dollars of the TOTAL purchase's cost.
6 0
3 years ago
Erica brought three and a half yards of fabric if she uses two thirds of it how much will she have left
Alecsey [184]
3 1/2 - (2/3)(3 1/2) = 

<span>7/2 - (2/3)(7/2) = </span>

<span>7/2 - 7/3 = </span>

<span>21/6 - 14/6 = </span>

<span>7/6 or 1 1/6 yds</span>
8 0
3 years ago
**PLS HELP! ILL GIVE BRAINLIEST**
lubasha [3.4K]

left = right

2.5 + x.5 = 11

10 + 5x = 11

5x = 1

x = 1/5

4 0
2 years ago
Read 2 more answers
How many pounds of a 15% copper alloy must be mixed with 700lb of a 30% copper alloy to maybe a 25.5% copper alloy
lisov135 [29]

Answer:

300\; \rm lb.

Step-by-step explanation:

Let x represent the mass (in pounds) of that 15\% copper alloy required, such that the final mixture would contain 25.5\% copper by mass.

Consider: if x pounds of that 15\% copper alloy is mixed with 700 pounds that 30\% copper alloy, what would be the mass of copper in the mixture?

  • Mass of copper in x pounds of that 15\% copper alloy: (0.15\, x)\; \rm lb.
  • Mass of copper in 700 pounds of that 30\% copper alloy: 700 \times 0.30 = 210\; \rm lb.

Therefore, the mixture would contain (210 + 0.15\, x) \; \rm lb of copper.

The mass of that mixture would be (700 + x)\; \rm lb. The mass fraction of copper in that mixture would be:

\displaystyle \frac{(210 + 0.15\, x)\; \rm lb}{(700 + x)\; \rm lb} \times 100\%.

This ratio is supposed to be equal to 25.5\%. These two pieces of equations combine to give an equation about x:

\displaystyle \frac{(210 + 0.15\, x)\; \rm lb}{(700 + x)\; \rm lb} \times 100\% = 25.5\%.

\displaystyle \frac{210 + 0.15\, x}{700 + x} = 0.255.

Simplify and solve for x:

210 + 0.15\, x= 0.255\, (700 + x).

(0.255 - 0.15)\, x= 210 - 0.255 \times 700.

\displaystyle x = \frac{210 - 0.255 \times 700}{0.255 - 0.15} = 300.

Therefore, 300\; \rm lb of that 15\% alloy would be required.

4 0
3 years ago
Which of the following is equivalent to 7(2x+1)-2(6x+3)=15
Ivenika [448]

Answer:

2x + 1 = 15

Step-by-step explanation:

4 0
2 years ago
Read 2 more answers
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