All categories

3 years ago

Help solve problem please

Mathematics

1 answer:

Naddika [18.5K]3 years ago

7 0

Answer:

1 / 13

Step-by-step explanation:

The total number of cards in a deck = 52

The total number of aces in a deck = 4

Since selection is drawn with replacement, then probability of drawing a certiaj number of card from the deck will be the same each time a selection is made :

Probability = required outcome / Total possible outcomes

The required outcome = number of aces = 4

Total possible outcomes = total number of cards = 52

P(drawing an ace) = 4 / 52 = 1 /13

You might be interested in

Robert is purchasing some packs of chicken from the supermarket. The first pack weights 45 ounces . The second pack weights 3 po

blagie [28]

Answer:

3 pounds duh

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

Someone please help! No link answer please :(

grandymaker [24]

Answer:

55 degrees (a)

Step-by-step explanation:

complementary means they equal 90 degrees

so 90-35= 55 degrees

3 0

3 years ago

The sum of three consecutive integers is -15.

zhuklara [117]

-18 maybe not to sure

4 0

1 year ago

Read 2 more answers

Use any of the methods to determine whether the series converges or diverges. Give reasons for your answer.

Aleks [24]

Answer:

It means $\sum_{n=1}^\inf} = \frac{7n^2-4n+3}{12+2n^6}$ also converges.

Step-by-step explanation:

The actual Series is::

$\sum_{n=1}^\inf} = \frac{7n^2-4n+3}{12+2n^6}$

The method we are going to use is comparison method:

According to comparison method, we have:

$\sum_{n=1}^{inf}a_n\ \ \ \ \ \ \ \ \sum_{n=1}^{inf}b_n$

If series one converges, the second converges and if second diverges series, one diverges

Now Simplify the given series:

Taking"n^2"common from numerator and "n^6"from denominator.

$=\frac{n^2[7-\frac{4}{n}+\frac{3}{n^2}]}{n^6[\frac{12}{n^6}+2]} \\\\=\frac{[7-\frac{4}{n}+\frac{3}{n^2}]}{n^4[\frac{12}{n^6}+2]}$

$\sum_{n=1}^{inf}a_n=\sum_{n=1}^{inf}\frac{[7-\frac{4}{n}+\frac{3}{n^2}]}{[\frac{12}{n^6}+2]}\ \ \ \ \ \ \ \ \sum_{n=1}^{inf}b_n=\sum_{n=1}^{inf} \frac{1}{n^4}$

Now:

$\sum_{n=1}^{inf}a_n=\sum_{n=1}^{inf}\frac{[7-\frac{4}{n}+\frac{3}{n^2}]}{[\frac{12}{n^6}+2]}\\ \\\lim_{n \to \infty} a_n = \lim_{n \to \infty} \frac{[7-\frac{4}{n}+\frac{3}{n^2}]}{[\frac{12}{n^6}+2]}\\=\frac{7-\frac{4}{inf}+\frac{3}{inf}}{\frac{12}{inf}+2}\\\\=\frac{7}{2}$

So a_n is finite, so it converges.

Similarly b_n converges according to p-test.

P-test:

General form:

$\sum_{n=1}^{inf}\frac{1}{n^p}$

if p>1 then series converges. In oue case we have:

$\sum_{n=1}^{inf}b_n=\frac{1}{n^4}$

p=4 >1, so b_n also converges.

According to comparison test if both series converges, the final series also converges.

It means $\sum_{n=1}^\inf} = \frac{7n^2-4n+3}{12+2n^6}$ also converges.

5 0

3 years ago

How can I find the x-intercept in a graph if the equation is 2x+3y=6

Varvara68 [4.7K]

Answer:

Step-by-step explanation:

First you would need to multiply 3y by zero since when finding x intercept, Y is always zero.

2x=6

next you would divide both sides by 2 and you get

X= 3 The ordered pair would be (3,0)

8 0

3 years ago