3(13-2a)=-3+a
39-6a=-3+a
42=7a
a=6
2. 
Domain: 
, because any value of 
is allowed and gives a number 
.
Range: 
, because 
for any positive real 
.
y-intercept: This is a point of the form 
. So plug in 
; we get 
. So the intercept is (0, 2), or just 2. (Interestingly, you didn't get marked wrong for that...)
Asymptote: This can be deduced from the range; the asymptote is the line 
.
Increasing interval: Going from left to right, there is no interval on which is increasing, since 1/4 is between 0 and 1.
Decreasing interval: Same as the domain; is decreasing over the entire real line.
End behavior: The range tells you 
, and you know is decreasing over its entire domain. This means that 
as 
, and 
and 
.
3. 
Domain: Same as (2), 
.
Range: We can rewrite 
. 
for all , so 
for all . Then the range is 
.
y-intercept: We have 
, so the intercept is (0, -6) (or just -6).
Asymptote: 
Increasing interval: Not increasing anywhere
Decreasing interval:
End behavior: Similar to (2), but this time as and 
as .
Answer:
if the triangular faces are equilateral, the prism is regular, in which case the rectangular faces are congruent. The rectangular faces are said to be lateral, while the triangular faces are bases. If the bases are horizontal, they are sometimes called the top and the bottom (faces).
Read more on Brainly.com - brainly.com/question/16526384#readmore
Step-by-step explanation:
I used a triangle generator, see picture attached
Answer:
Step-by-step explanation:
Since this is a test/hw, I'll give a hint.
This problem at first can seem a bit difficult with q's and power's everywhere.
But let's take a step backward. A power is when your mutiplying something by itself again and again.
Ex: 3^3=3 times 3 times 3
But what if we had something liiiike this:
(3^3)2
In this case its now
(3 times 3 times 3)^2, so its "techinicaly" (27)^2. And you would a fairly large number, which I'm to lazy to solve. But that's not the point.
We've seen what a power is deconstructed, and what a power is. Because my explantion probably confused you more than it helped, I'll give an example.
(2^2)^2=(2 times 2)^2=(4^2=16=2^4
However, there is a shorter way to solve it.
(2^2)^2=2^(2 times 2)=2^4
Hope this helps.
