Answer:
Why wont anyone help me please
Answer:
Part 5.1.1:

Part 5.1.2:

Step-by-step explanation:
We are given that:

Part 5.1.1
Recall that:

Let θ = 2<em>A</em>. Hence:

Square the original equation:

Hence:

Subtract:

Take the square root of both sides:

Since 0° ≤ 2<em>A</em> ≤ 90°, cos(2<em>A</em>) must be positive. Hence:

Part 5.1.2
Recall that:

We can use the third form. Substitute:

Solve for cosine:

In conclusion:

(Note that since 0° ≤ 2<em>A</em> ≤ 90°, 0° ≤ <em>A</em> ≤ 45°. Hence, cos(<em>A</em>) must be positive.)
Answer:
12
Step-by-step explanation:
The area of a parallelogram is equal to its base times its height. Segment DX is a height relative to the base BC, so (area of ABCD) = BC times DX,
144 = 12 times DX.
So, DX is 12. :)
0 < /6/ (absolute value)
That is your inequality since the subject is about the distance away from zero then using common sense you would make the 6 get put in between the 2 absolute value lines ( not trying to be rude, if the explanation seems rude to you im sorry)