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kipiarov [429]
3 years ago
13

Many insects migrate (travel) between their summer and winter homes. The desert locust migrates about 800 miles farther than the

Monarch butterfly every spring, and the pink-spotted hawk moth migrates about 200 miles less than four times the distance of the Monarch butterfly every spring. Laid end to end, the distances traveled by a Monarch butterfly, a desert locust, and a pink-spotted hawk moth is about 12600 miles every spring. How far does each species travel?
Mathematics
1 answer:
Harman [31]3 years ago
6 0

Answer:

Distance travelled by Monarch butterfly = 2000 miles

Distance travelled by desert locust  = 2800

Distance travelled by pink-spotted hawk moth= 7800 miles

Step-by-step explanation:

Let the distance travelled by Monarch butterfly  be "X" miles

Distance travelled by desert locust is equal to X + 800 miles

Distance travelled by pink-spotted hawk moth is equal to 4X -200 miles

The total distance travelled by the three is equal to 12600 miles

X + X + 800 + 4X -200 = 12600\\6X = 12600 -600\\6X = 12000\\X = 2000

Distance travelled by Monarch butterfly = 2000 miles

Distance travelled by desert locust  = 2000 + 800 = 2800

Distance travelled by pink-spotted hawk moth = 4 * 2000 -200 = 7800 miles

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1. Suppose that a theater charges a school group $4.50 per student to show a special film. Suppose that the theater's operating
elixir [45]

The functions I(x) and E(x) of the theatre's income and expenses are illustrations of linear functions.

<h3>The equation of the theatre's income</h3>

The theatre charges $4.50 per student.

Assume the number of students is x, the equation of the theatre's income would be:

I(x) = 4.5x

<h3>The equation of the theatre's expenses</h3>

The theatre expense per student is $1.25, and the operating cost on the staff is $130

The equation of the theatre's expenses would be:

E(x) = 1.25x + 130

<h3>Complete the table</h3>

Using the formulas I(x) = 4.5x and E(x) = 1.25x + 130, the complete table is:

Students, x  0       10        20     30      40      50      60    70

Income, I      0      45        90     135     180    225    270   315

Expenses, E 130  142.5   155    167.5   180   192.5   205  217.5

<h3>The graph of the theatre's income and expenses</h3>

See attachment

<h3>The pattern by which theatre's income and expenses increase</h3>

The functions I(x) and E(x) are linear functions.

So, the pattern with which the functions increase is a linear pattern.

<h3>The number of students when the theatre's income and expenses are equal</h3>

This means that:

I(x) = E(x)

So, we have:

4.5x = 1.25x + 130

Subtract 1.25 from both sides

3.25x = 130

Divide both sides by 3.25

x = 40

Hence, the number of students is 40

<h3>The theatre profit</h3>

This is the difference between the theatre expenses and their income.

So, we have:

P(x) = E(x) - I(x)

This gives

P(x) = 1.25x + 130 - 4.5x

Simplify

P(x) = 130 - 3.25x

<h3>Solution to the inequalities</h3>

We have:

E(x) < 255

This gives

1.25x + 130 < 255

Subtract 130 from both sides and divide by 1.25

x < 100 students

Also, we have:

I(x) > 675

This gives

4.5x > 657

Solve for x

x > 146 students

Hence, the number of students for the inequalities are less than 100 and greater than 146

Read more about linear equations and inequalities at:

brainly.com/question/11234618

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The answer would be 2(4x + 3y) cause the 2 gets multiplied by the numbers in the parentheses so 2x4x = 8x and 2x 3y = 6y
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