Ok so Candy draws a square design with a side length of x inches for the window at the pet shop. She takes the design to the printer and asks for a sign that has an area of
16x^2-40x+25square inches.
Let y(x) =16x^2-40x+25
If differentiating both sides w.r.t x we get
y'(x)=32x-40
And
to find critical point x ,Put y'(x)=0 then
32x-40=0
x=5/4
Answer:
10
Step-by-step explanation:
Let "a number" = x
4(x - 4) = 24
Isolate the x. First, divide 4 from both sides
(4(x -4))/4 = (24)/4
x - 4 = 6
Add 4 to both sides
x - 4 (+4) = 6 (+4)
x = 6 + 4
x = 10
10 is your answer for "a number"
Given:
The minimum and maximum distance that the dog may be from the house can be found by using the equation:

To find:
The minimum and maximum distance that the dog may be from the house.
Solution:
We have,

It can be written as:

Adding 500 on both sides, we get

Now,
and 
and 
The minimum distance is 492 meters and the maximum distance is 508 meters.
Therefore, the correct option is C.
The unit circle is represented below:
As can be observed in the figure above, for an angle (t), the relation between the trigonometric functions and x and y components is:
x = cos(t)
y = sen(t)
x is positive in the first and in the fourth quadrant. Thus, cos (t) will be positive for angles in the first and fourth quadrant.
y is positive in the first and in the second quadrant. Thus, sin (t) will be positive for angles in the first and second quadrant.
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