Step-by-step explanation:
4 and 5 is one 20/25
1060.5263157 etc your teacher prob tells you to round
Answer:
there is no greatest load
Step-by-step explanation:
Let x and y represent the load capacities of my truck and my neighbor's truck, respectively. We are given two relations:
x ≥ y +600 . . . . . my truck can carry at least 600 pounds more
x ≤ (1/3)(4y) . . . . . my truck carries no more than all 4 of hers
Combining these two inequalities, we have ...
4/3y ≥ x ≥ y +600
1/3y ≥ 600 . . . . . . . subtract y
y ≥ 1800 . . . . . . . . multiply by 3
My truck's capacity is greater than 1800 +600 = 2400 pounds. This is a lower limit. The question asks for an <em>upper limit</em>. The given conditions do not place any upper limit on truck capacity.
A = 6, 2
B = 3, 4
C = -10, 3
D = -4, 5
E = -5, -3
F = -4, -2
G = 3, -8
7x^4 +7/x^2 on the interval [-2,3]
