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Alinara [238K]
2 years ago
7

What two numbers multiply to 6 and add to 31 ?

Mathematics
2 answers:
Paraphin [41]2 years ago
8 0

Answer:

why would i know ?

Step-by-step explanation:

Tanzania [10]2 years ago
4 0
6x6= 36
6x5= 30
So it’s not possible to multiply 6 by anything and get 31.
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Suppose twenty-two communities have an average of = 123.6 reported cases of larceny per year. assume that σ is known to be 36.8
Delvig [45]
We are given the following data:

Average = m = 123.6
Population standard deviation = σ= psd = 36.8
Sample Size = n = 22

We are to find the confidence intervals for 90%, 95% and 98% confidence level.

Since the population standard deviation is known, and sample size is not too small, we can use standard normal distribution to find the confidence intervals.

Part 1) 90% Confidence Interval
z value for 90% confidence interval = 1.645

Lower end of confidence interval = m-z *\frac{psd}{ \sqrt{n} }
Using the values, we get:
Lower end of confidence interval=123.6-1.645* \frac{36.8}{ \sqrt{22}}=110.69

Upper end of confidence interval = m+z *\frac{psd}{ \sqrt{n} }
Using the values, we get:
Upper end of confidence interval=123.6+1.645* \frac{36.8}{ \sqrt{22}}=136.51

Thus the 90% confidence interval will be (110.69, 136.51)

Part 2) 95% Confidence Interval
z value for 95% confidence interval = 1.96

Lower end of confidence interval = m-z *\frac{psd}{ \sqrt{n} }
Using the values, we get:
Lower end of confidence interval=123.6-1.96* \frac{36.8}{ \sqrt{22}}=108.22

Upper end of confidence interval = m+z *\frac{psd}{ \sqrt{n} }
Using the values, we get:
Upper end of confidence interval=123.6+1.96* \frac{36.8}{ \sqrt{22}}=138.98

Thus the 95% confidence interval will be (108.22, 138.98)

Part 3) 98% Confidence Interval
z value for 98% confidence interval = 2.327

Lower end of confidence interval = m-z *\frac{psd}{ \sqrt{n} }
Using the values, we get:
Lower end of confidence interval=123.6-2.327* \frac{36.8}{ \sqrt{22}}=105.34
Upper end of confidence interval = m+z *\frac{psd}{ \sqrt{n} }
Using the values, we get:
Upper end of confidence interval=123.6+2.327* \frac{36.8}{ \sqrt{22}}=141.86

Thus the 98% confidence interval will be (105.34, 141.86)


Part 4) Comparison of Confidence Intervals
The 90% confidence interval is: (110.69, 136.51)
The 95% confidence interval is: (108.22, 138.98)
The 98% confidence interval is: (105.34, 141.86)

As the level of confidence is increasing, the width of confidence interval is also increasing. So we can conclude that increasing the confidence level increases the width of confidence intervals.
3 0
3 years ago
The equation 4(x-2) = 100 is a true equation for a particular value of x. Explain why 2(x-2) = 50 is also true for the same valu
Mazyrski [523]

Answer:Figure it out your self.

Step-by-step explanation:

8 0
3 years ago
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What kind of angle is formed by the tangent to a circle and a radius of that circle?
Vsevolod [243]
A tangent is always perpendicular to the radius at the point of tangency.

A right angle.
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3 years ago
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(-10x-8)-70 (4x-11) + 46 -43(6x6) -54+ (8x5)
STatiana [176]
I feel like you just put random numbers in to waste someone time... but I did the problem any way.

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3 years ago
Find the area of the rectangle.<br> 36<br> kilometers<br> (x-3) kilometers
Vika [28.1K]

Answer:

36x - 108 kilometers²

Step-by-step explanation:

Area = length x width

36 ( x - 3 ) =

36x - 108

-Chetan K

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2 years ago
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